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3/4(8k-4)=-3+6k Identity or no solution? :)

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is this yor question \[\frac{ 3 }{ 4 }(8k-4)=-3+6k\]
were ya sleeping lol

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\[3*2k-1=-3+6k\] 6k-1= -3 +6k so it has got no solution , don sleep cat lolhahaha
Im just checking my answer if im right
Your answer is not same as mine
cus ya solved wrong
Hmm, i'm not sure who's right :) how did you get the answer for 3/4(8k-4)?
\[\frac{ 3 }{ 4 }(8k-4)=-3+6k \\\frac{ 3 \dot\ 4 }{ 4 }(2k-1)=-3+6k \\3(2k - 1) = -3 + 6k \\6k - 3 = -3 + 6k \\6k - 3 = 6k - 3 \] Identity
Oh thanks, we have the same answer :) i'm just confused for the answer
ma honest mistake
6k - 3 = 6k - 3 6k - 6k = 3 - 3 0 = 0 Identity

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