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Kittykatkat14

  • 3 years ago

3/4(8k-4)=-3+6k Identity or no solution? :)

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  1. jasonxx
    • 3 years ago
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    is this yor question \[\frac{ 3 }{ 4 }(8k-4)=-3+6k\]

  2. Kittykatkat14
    • 3 years ago
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    Yes

  3. jasonxx
    • 3 years ago
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    were ya sleeping lol

  4. Kittykatkat14
    • 3 years ago
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    Huh?

  5. jasonxx
    • 3 years ago
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    \[3*2k-1=-3+6k\] 6k-1= -3 +6k so it has got no solution , don sleep cat lolhahaha

  6. Kittykatkat14
    • 3 years ago
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    Im just checking my answer if im right

  7. jasonxx
    • 3 years ago
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    cool

  8. Kittykatkat14
    • 3 years ago
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    Your answer is not same as mine

  9. jasonxx
    • 3 years ago
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    cus ya solved wrong

  10. Kittykatkat14
    • 3 years ago
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    Hmm, i'm not sure who's right :) how did you get the answer for 3/4(8k-4)?

  11. Hero
    • 3 years ago
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    \[\frac{ 3 }{ 4 }(8k-4)=-3+6k \\\frac{ 3 \dot\ 4 }{ 4 }(2k-1)=-3+6k \\3(2k - 1) = -3 + 6k \\6k - 3 = -3 + 6k \\6k - 3 = 6k - 3 \] Identity

  12. Kittykatkat14
    • 3 years ago
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    Oh thanks, we have the same answer :) i'm just confused for the answer

  13. jasonxx
    • 3 years ago
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    ma honest mistake

  14. Hero
    • 3 years ago
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    6k - 3 = 6k - 3 6k - 6k = 3 - 3 0 = 0 Identity

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