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ERoseM

  • 3 years ago

Find any relative extrema and inflection points of the function. Use a graphing utility to confirm your results y= x ln x

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  1. shubhamsrg
    • 3 years ago
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    find dy/dx..set that equal to 0 for points of inflection or maximas/minimas..

  2. tcarroll010
    • 3 years ago
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    Using the product rule, you have: (x)(ln x)' + (ln x)(x)' = 1 + ln x = y' So, y' = 0 at e^(-1) So, that is your minimum, and the function is defined for x > 0. The second derivative is 1/x so the whole graph is concave up. Graph attached.

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  3. ERoseM
    • 3 years ago
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    Thank you. I appreciate it!

  4. tcarroll010
    • 3 years ago
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    You're welcome!

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