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anonymous
 4 years ago
Find any relative extrema and inflection points of the function. Use a graphing utility to confirm your results
y= x ln x
anonymous
 4 years ago
Find any relative extrema and inflection points of the function. Use a graphing utility to confirm your results y= x ln x

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shubhamsrg
 4 years ago
Best ResponseYou've already chosen the best response.0find dy/dx..set that equal to 0 for points of inflection or maximas/minimas..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Using the product rule, you have: (x)(ln x)' + (ln x)(x)' = 1 + ln x = y' So, y' = 0 at e^(1) So, that is your minimum, and the function is defined for x > 0. The second derivative is 1/x so the whole graph is concave up. Graph attached.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you. I appreciate it!
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