Consider the polynomial P(x) = ax^4 - x^3 - 14x^2 + bx - 6 where a and b are constant. If one of the zeros of P(x) is 2 and the remainder is -36 when P(x) is devided by (x + 1). Find the values of a and b. How do I solve this?

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it means P(2) = 0 and P(-1) = -36 now, aplly of them to P(x)

okay got the asnwers. thank you very much!

a=6, b=-13, right ?

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