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anonymous
 3 years ago
Find any relative extrema and inflection points of the function. Use a graphing utility to confirm your results y= x ln x
anonymous
 3 years ago
Find any relative extrema and inflection points of the function. Use a graphing utility to confirm your results y= x ln x

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ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.0First: because of the lnfunction, x > 0. Differentiate:\[\frac{ dy }{ dx }=1*\ln x+x* \frac{ 1 }{ x }=\ln x+1\] Now solve\[\frac{ dy }{ dx }=0\]to find the xvalue(s) where the graph has a horizontal tangent line. With the aid of a sign scheme of the derivative you can establish whether these xvalues are related to a min/max value or that there is an inflection point. To find additional inflection points, you should differentiate once more, and solve y''=0. You get an inflection point if there is a sign change around the solution of y''=0.
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