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Lukecrayonz

  • 3 years ago

Find all solutions in the interval [0, 2π). sec^2 x - 2 = tan^2 x HELP! :o

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  1. Lukecrayonz
    • 3 years ago
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    I'm pretty sure the answer is no solution..

  2. RadEn
    • 3 years ago
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    there is no solution... maybe, the typo there

  3. ChmE
    • 3 years ago
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    \[\sec^2 x - 2 = \tan^2 x \]\[\sec^2 x - 1 = \tan^2 x +1\]\[\sec^2x=\tan^2x+1\]\[\sec^2x-1=\sec^2x\]\[-1 \not= 0\]No Solution

  4. Lukecrayonz
    • 3 years ago
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    okay thank you so much! can you help me with one more question? @ChmE

  5. ChmE
    • 3 years ago
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    sure

  6. Lukecrayonz
    • 3 years ago
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    A high-altitude spherical weather balloon expands as it rises due to the drop in atmospheric pressure. Suppose that the radius r increases at the rate of 0.16 inches per second and that r = 38 inches at time t = 0. Determine the equation that models the volume V of the balloon at time t and find the volume when t = 280 seconds.

  7. ChmE
    • 3 years ago
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    btw here is a good reference site for these types of problems http://www.sosmath.com/trig/Trig5/trig5/trig5.html

  8. ChmE
    • 3 years ago
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    idk sry. I can't do word problems

  9. Lukecrayonz
    • 3 years ago
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    I have another then! @ChmE

  10. Lukecrayonz
    • 3 years ago
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    Find the inverse of 3√(x/8) -4

  11. ChmE
    • 3 years ago
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    \[3\sqrt{{x \over 8} -4}\]is this the question

  12. Lukecrayonz
    • 3 years ago
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    yes! the three is the little number

  13. Lukecrayonz
    • 3 years ago
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    @sirm3d help with the inverse question please!

  14. sirm3d
    • 3 years ago
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    starting with x, divide by 8, subtract by 4, take the cube root Inverse: starting with x, cube it, add 4, then multiply by 8

  15. sirm3d
    • 3 years ago
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    it's like socks before shoes. the inverse: shoes before socks

  16. sirm3d
    • 3 years ago
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    the inverse of the function is \[\large (x^3+4)(8)\]

  17. Lukecrayonz
    • 3 years ago
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    thank you! you're a lifesaver

  18. sirm3d
    • 3 years ago
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    ^^

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