Find all solutions in the interval [0, 2π). sec^2 x - 2 = tan^2 x HELP! :o

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Find all solutions in the interval [0, 2π). sec^2 x - 2 = tan^2 x HELP! :o

Mathematics
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I'm pretty sure the answer is no solution..
there is no solution... maybe, the typo there
\[\sec^2 x - 2 = \tan^2 x \]\[\sec^2 x - 1 = \tan^2 x +1\]\[\sec^2x=\tan^2x+1\]\[\sec^2x-1=\sec^2x\]\[-1 \not= 0\]No Solution

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okay thank you so much! can you help me with one more question? @ChmE
sure
A high-altitude spherical weather balloon expands as it rises due to the drop in atmospheric pressure. Suppose that the radius r increases at the rate of 0.16 inches per second and that r = 38 inches at time t = 0. Determine the equation that models the volume V of the balloon at time t and find the volume when t = 280 seconds.
btw here is a good reference site for these types of problems http://www.sosmath.com/trig/Trig5/trig5/trig5.html
idk sry. I can't do word problems
I have another then! @ChmE
Find the inverse of 3√(x/8) -4
\[3\sqrt{{x \over 8} -4}\]is this the question
yes! the three is the little number
@sirm3d help with the inverse question please!
starting with x, divide by 8, subtract by 4, take the cube root Inverse: starting with x, cube it, add 4, then multiply by 8
it's like socks before shoes. the inverse: shoes before socks
the inverse of the function is \[\large (x^3+4)(8)\]
thank you! you're a lifesaver
^^

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