cory_ryan
find the dot product v⋅w:
for v=i-j, w=i+j
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richyw
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\[\mathbf{v}\cdot\mathbf{w}=\langle 1,-1\rangle\cdot\langle 1,1\rangle\]\[=1(1)+-1(1)=0\]
cory_ryan
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do you know how i would find the angle to that?
richyw
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plot those two vectors onto a graph.
cory_ryan
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ok and find the missing angle?
richyw
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you can also use is the fact that for two vectors with magnitudes \(a\) and \(b\), with angle \(\theta\) between the two vectors, the dot product is\[\mathbf{a}\cdot\mathbf{b}=ab\cos{\theta}\]
richyw
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so \(0=\cos{\theta}\)
cory_ryan
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ok thats simple
cory_ryan
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thanks bro