A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
please help find the equations of the tangents to these circles at the points given x^2 + y^2 +2x + 4y  12 = 0 (3, 1)
anonymous
 4 years ago
please help find the equations of the tangents to these circles at the points given x^2 + y^2 +2x + 4y  12 = 0 (3, 1)

This Question is Closed

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0the circle will have a tangent at x = 3 which is in the top half of the circle as the centre is (1, 2) you need to get the equation of the circle with y as the subject (x + 1)^2 + (y + 2)^2 = 12  1  4 or (x +1)^2 + (y + 2)^2 = 7 (y + 2)^2 = 7  (x + 1)^2 \[y + 2 = \pm \sqrt{7  (x + 1)^2}\] so \[y = \pm \sqrt{7  (x + 1)^2}  2\] so you need to differentiate the which is the upper semicircle \[y = \sqrt{7  (x + 1)^2}  2\] and then substitute the find the slope of the tangent... once you have the slope... then use the point (3, 1) to find the equations... hope it helps.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i cam't differentiate as we haven't learnt it yet ?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.