## samnatha Group Title please help find the equations of the tangents to these circles at the points given x^2 + y^2 +2x + 4y - 12 = 0 (3, -1) one year ago one year ago

the circle will have a tangent at x = 3 which is in the top half of the circle as the centre is (-1, -2) you need to get the equation of the circle with y as the subject (x + 1)^2 + (y + 2)^2 = 12 - 1 - 4 or (x +1)^2 + (y + 2)^2 = 7 (y + 2)^2 = 7 - (x + 1)^2 $y + 2 = \pm \sqrt{7 - (x + 1)^2}$ so $y = \pm \sqrt{7 - (x + 1)^2} - 2$ so you need to differentiate the which is the upper semicircle $y = \sqrt{7 - (x + 1)^2} - 2$ and then substitute the find the slope of the tangent... once you have the slope... then use the point (3, -1) to find the equations... hope it helps.