Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

samnatha

  • 3 years ago

please help find the equations of the tangents to these circles at the points given x^2 + y^2 +2x + 4y - 12 = 0 (3, -1)

  • This Question is Closed
  1. campbell_st
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the circle will have a tangent at x = 3 which is in the top half of the circle as the centre is (-1, -2) you need to get the equation of the circle with y as the subject (x + 1)^2 + (y + 2)^2 = 12 - 1 - 4 or (x +1)^2 + (y + 2)^2 = 7 (y + 2)^2 = 7 - (x + 1)^2 \[y + 2 = \pm \sqrt{7 - (x + 1)^2}\] so \[y = \pm \sqrt{7 - (x + 1)^2} - 2\] so you need to differentiate the which is the upper semicircle \[y = \sqrt{7 - (x + 1)^2} - 2\] and then substitute the find the slope of the tangent... once you have the slope... then use the point (3, -1) to find the equations... hope it helps.

  2. samnatha
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i cam't differentiate as we haven't learnt it yet ?

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy