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anonymous
 3 years ago
please help find the equations of the tangents to these circles at the points given x^2 + y^2 +2x + 4y  12 = 0 (3, 1)
anonymous
 3 years ago
please help find the equations of the tangents to these circles at the points given x^2 + y^2 +2x + 4y  12 = 0 (3, 1)

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campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0the circle will have a tangent at x = 3 which is in the top half of the circle as the centre is (1, 2) you need to get the equation of the circle with y as the subject (x + 1)^2 + (y + 2)^2 = 12  1  4 or (x +1)^2 + (y + 2)^2 = 7 (y + 2)^2 = 7  (x + 1)^2 \[y + 2 = \pm \sqrt{7  (x + 1)^2}\] so \[y = \pm \sqrt{7  (x + 1)^2}  2\] so you need to differentiate the which is the upper semicircle \[y = \sqrt{7  (x + 1)^2}  2\] and then substitute the find the slope of the tangent... once you have the slope... then use the point (3, 1) to find the equations... hope it helps.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i cam't differentiate as we haven't learnt it yet ?
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