the lengths of the tree sides of a triangle are denoted a,b, and c; the angles opposiete these sides are A,B,C. use the given information to find the required quantities.
a) B= 90 deg.; cotA=4/3; b=5 sqrt2; FIND a.
b) b=10 cm, c=10cm, A = 60 deg. FIND area of ABC TRIANGLE.
I can start if off but i dont know what to do next?
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the lengths of the tree sides of a triangle are denoted a,b, and c; the angles opposiete these sides are A,B,C. use the given information to find the required quantities.
a) B= 90 deg.; cotA=4/3; b=5 sqrt2; FIND a.
b) b=10 cm, c=10cm, A = 60 deg. FIND area of ABC TRIANGLE.
I can start if off but i dont know what to do next?
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
the lengths of the tree sides of a triangle are denoted a,b, and c; the angles opposiete these sides are A,B,C. use the given information to find the required quantities.
a) B= 90 deg.; cotA=4/3; b=5 sqrt2; FIND a.
Take the figure; note that the sides are a, b, and c. The angles opposite to these are A, B, and C. This means (look at the figure).
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okay then, so basically the cot is 1/ tan, or the tangent just opposite so instead of oppoiste over adj. its adj/ opposite? and that is how we got the a, right?
So the angles of triangle ABC would be
60 + x + x = 180
60 + 2x = 180
2x = 180 - 60
2x = 120
x = 120/2 = 60
So, angle B = angle C = 60 degrees.
Triangle ABC is an equilateral triangle, so the area of an equilateral triangle is given by \[Area = \frac{ s ^{2}*\sqrt{3} }{ 4 } = \frac{ (10)^{2}*\sqrt{3} }{ 4 } = \frac{ 100\sqrt{3} }{ 4 }\]