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t.prentice

  • 2 years ago

What is the antiderivative of 2t^2*sqrt t+1/(t*sqrt t)

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  1. SomeBloke
    • 2 years ago
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    Do you mean the antiderivative of the following?\[2t ^{2}\sqrt{t}+\frac{ 1 }{ t \sqrt{t} }\]What difficulty are you having? How far have you got with it? Remember the following:-\[\sqrt{x}=x ^{\frac{ 1 }{ 2 }} \text{(Nonnegative values only.)}\]\[x^{a} x^{b}=x^{a+b}\]\[d(u+v)=du+dv\]

  2. JulioMarco
    • 2 years ago
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    I suggest you to use sqrt(2) instead of sqrt 2 for us to better understand your formulae. Could you restate your question using that notation? Cheers!

  3. PRATIKSINHA
    • 2 years ago
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    IT WOULD BE-(4(T^3.5)/7 )-2T^(-0.5) +C

  4. Krishnadas
    • 2 years ago
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    |dw:1355916670782:dw|

  5. Krishnadas
    • 2 years ago
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    @PRATIKSINHA how did you got that starting minus in your answer?

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