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\[A = \left[\begin{matrix}6 & -2 \\ -2 & 3\end{matrix}\right]\]

Are you learning about SVD (singular value decomposition)?

nope....

but A is symmetric, so I think its eig vectors are orthogonal

but I'm not sure about this finding P business.....

The way trhe book started out was finding the eigen values which I got to be 3 and 6.

are you sure about the eigenvalues??

yeah

because I do not get 3 and 6

actually h/o.

I guess I did that wrong lol now i'm konfused with that :P

yeah that's what I thought... (6-L) (3-L) - (-2)(-2) = 18 - 9L +L^2 -4

18 - 9L +L^2 -4=0

yeah :)

L^2 -9L +14=0

this factors

mhm

you don't know how to factor?

Sorry I had to do some holiday stuff.....

and that makes sense yeah.

not completely, I kind of left mid way for something.

Save me please :). 2 Questions 1 hour... :(.

How do we find the normal EV's again?
and what trick?