Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Solve the logarithmic equation. Be sure to reject and value of x that is not in the domain of the original logarithmic expression. Give the exact answer. log4(x+8)+log4(x-4)=3 (the 4 after the logs are subscript)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
What do you know about logs and what they *can't* be used to calculate?
I'm confused about the part about rejecting values of x that are not in the domain.
How do I know which value of x to use? When I take my x values and plug them back into the equation, more than one x value fits and makes everything come out correctly but I am unsure about which one to put down for answer.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I am using MyMathLab so it's very sensitive, and I have to put in the exact correct answer
Can you take a log of a negative number?
No
Good. And what about 0?
No
Perfect. So you know, then, that each of your logs have to be > 0. That's the limitation of your domain.
I put in x=8 on my MathLab and got it right! You made it so easy for me, thank you!
Yes, it is 8, but I want to make sure you know why.
x^2-4x+8x-32=4^3 x^2+4x-32=64 -64 -64 x^2+4x-96=0 x-8=0 x+12=0 x=8 x=-12
Oh, good! Nice job.
(8)^2-4(8)-32=0 64-32-32=0 0=0
Thanks. I know how to get there, just not which X to use

Not the answer you are looking for?

Search for more explanations.

Ask your own question