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What do you know about logs and what they *can't* be used to calculate?

I'm confused about the part about rejecting values of x that are not in the domain.

I am using MyMathLab so it's very sensitive, and I have to put in the exact correct answer

Can you take a log of a negative number?

No

Good. And what about 0?

No

I put in x=8 on my MathLab and got it right! You made it so easy for me, thank you!

Yes, it is 8, but I want to make sure you know why.

x^2-4x+8x-32=4^3
x^2+4x-32=64
-64 -64
x^2+4x-96=0
x-8=0 x+12=0
x=8 x=-12

Oh, good! Nice job.

(8)^2-4(8)-32=0
64-32-32=0
0=0

Thanks. I know how to get there, just not which X to use