## anonymous 3 years ago Help me ?):

1. anonymous

if f(x)= 1/x+2, what is f^-1(x)?

2. anonymous

f(x)=y=1/x+2 you need to solve for x with these inverse problems which just means rearranging your equation to isolate x on one side of the equations since y=1/x+2 your next step would be to subtract the 2 y-2=1/x your next step would be to multiply by x x(y-2)=1 then divide by y-2 x=1/(y-2)

3. anonymous

i got $f^-1(x)=\frac{ 1 }{ x-2 }$

4. anonymous

y should be on the bottom 1/y-2

5. anonymous

@jim_thompson5910

6. anonymous

@zepdrix

7. zepdrix

$\large f(x)=\frac{1}{x+2}$ $\large g(x)=\frac{1}{x}+2$ Which one is the correct format, f or g? :)

8. anonymous

f?

9. zepdrix

$\large \text{Let}\quad f(x)=y, \qquad \rightarrow \qquad y=\frac{1}{x+2}$Taking the inverse gives us,$\large x=\frac{1}{y+2}$Multiply both sides by (y+2), giving us,$\large x(y+2)=1$Divide both sides by x,$\large (y+2)=\frac{1}{x}$Subtract 2 from each side,$\large y=\frac{1}{x}-2$Rewrite with inverse notation,$\large f^{-1}(x)=\frac{1}{x}-2$

10. zepdrix

I came up with something slightly different katie :D lemme know if those steps make sense.

11. anonymous

i see thank you(: