Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Ldaniel
Group Title
for what value(s) of k will f(x)=x^3kx^2+kx+k have an inflection point at x=5?
 one year ago
 one year ago
Ldaniel Group Title
for what value(s) of k will f(x)=x^3kx^2+kx+k have an inflection point at x=5?
 one year ago
 one year ago

This Question is Closed

SomeBloke Group TitleBest ResponseYou've already chosen the best response.2
You're still not saying what actual difficulties you're having. Do you know how to find inflection points?
 one year ago

JulioMarco Group TitleBest ResponseYou've already chosen the best response.0
If you wish to find inflection points, just take the structural form of the derivative (its formula) and find the places where it equals zero. An inflection point will be a point with zero derivative and with derivatives of different signs before and after it.
 one year ago

SomeBloke Group TitleBest ResponseYou've already chosen the best response.2
No, JulioMarco, those aren't inflection points. Those are maxima and minima you're describing. At an inflection point, it's the second derivative that's zero, since a function's inflection points are at maxima and minima of its first derivative. An inflection point of f(x) at x will be a maximum or minimum of f'(x) at x, and so f''(x)=0 at x.
 one year ago

asimo3 Group TitleBest ResponseYou've already chosen the best response.0
SomeBloke is right, its when d^2(f(x))/d(x^2)=0, inflections points are found by taking the 2nd derivative and setting them to 0.
 one year ago

JulioMarco Group TitleBest ResponseYou've already chosen the best response.0
SomeBloke and Asimo, you are completely right... I wrote it in the wrong way, thank you! :)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.