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jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1f(x)=x^3kx^2+kx+k f ' (x)=3x^22kx+k ... derive f '' (x)=6x2k ... derive again You want the point of inflection to be at x = 5, so you want f '' (5) = 0 f '' (x)=6x2k f '' (5)=6*52k f '' (5)=302k 0=302k now solve for k
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