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\[\int\limits_{-2}^{0} (\frac{ 1 }{ 2 }t^4+\frac{ 1 }{ 4 }t^3-t)dt\]

Hint.
\[\int\limits_{?}^{?} t ^{4} =\frac{ t ^{4+1} }{ 4+1}\]

are you familiar with the general formula of integration?

I'm familiar with... \[\int\limits_{a}^{b} f(x)dx=F(x)|_{a}^{b} = F(b)-F(a)\]

ya this is done when we apply the limits but do you know how we do integration?

I don't.

the general formula for integration of \(\int x^n dx = \frac{x^n+1}{n+1} +C\)

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now use your calculator to punch in those suckers

can you explain the [...]_{-2}^{0}

∫abf(x)dx=F(x)|ba=F(b)−F(a) <--this is why.

from your original post up there.

ohhh so i do apply that.. I just missed a step.

yup :) i think you've got it.

thank you guys! (: you're amazing!

you're welcome :)

-21/5?

err... let me recheck my work.

sorry, my mistake. i typed wrong. lol no neg.

oh okay (: is that the answer though? because what happens with the .... +C?

oh okay (: so 21/5 it is?

yup! :)

thanks again!

you're welcome :)