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monroe17
 3 years ago
someone help? (:
monroe17
 3 years ago
someone help? (:

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monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{2}^{0} (\frac{ 1 }{ 2 }t^4+\frac{ 1 }{ 4 }t^3t)dt\]

nubeer
 3 years ago
Best ResponseYou've already chosen the best response.0Hint. \[\int\limits_{?}^{?} t ^{4} =\frac{ t ^{4+1} }{ 4+1}\]

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0I honestly don't even know how to solve or begin to solve for it.. can you help me step by step? I have 7 more problems like this and I'd like to do them all myself.. But I need help solving and the steps to do so.

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1are you familiar with the general formula of integration?

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0I'm familiar with... \[\int\limits_{a}^{b} f(x)dx=F(x)_{a}^{b} = F(b)F(a)\]

nubeer
 3 years ago
Best ResponseYou've already chosen the best response.0ya this is done when we apply the limits but do you know how we do integration?

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1the general formula for integration of \(\int x^n dx = \frac{x^n+1}{n+1} +C\)

winterfez
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355140890023:dw

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1@winterfez i believe that's \(\left[ \frac{1}{2} \frac{t^5}{5}+\frac{1}{4} \frac{t^4}{4} \frac{t^2}{2} \right]^0_{2}\)

winterfez
 3 years ago
Best ResponseYou've already chosen the best response.0\[(\frac{ 1 }{ 2 }\frac{ 0 }{ 5 }+\frac{ 1 }{ 4 }\frac{ 0^{4} }{ 4 }\frac{ 0 }{ 2 })(\frac{ 1 }{ 2 }\frac{ (2)^5 }{ 5 }+\frac{ 1 }{ 4 }\frac{ (2)^4 }{ 4 }\frac{ (2)^{2} }{ 2 })\]

winterfez
 3 years ago
Best ResponseYou've already chosen the best response.0now use your calculator to punch in those suckers

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0can you explain the [...]_{2}^{0}

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1∫abf(x)dx=F(x)ba=F(b)−F(a) <this is why.

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1from your original post up there.

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh so i do apply that.. I just missed a step.

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1yup :) i think you've got it.

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0thank you guys! (: you're amazing!

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0I got 21/5.. does that seem right @Shadowys

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0err... let me recheck my work.

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1sorry, my mistake. i typed wrong. lol no neg.

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay (: is that the answer though? because what happens with the .... +C?

Shadowys
 3 years ago
Best ResponseYou've already chosen the best response.1well. that's for indefinite integrals because you don't know where is the limit. the C is gone when it is definite.

monroe17
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay (: so 21/5 it is?
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