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monroe17Best ResponseYou've already chosen the best response.0
\[\int\limits_{2}^{0} (\frac{ 1 }{ 2 }t^4+\frac{ 1 }{ 4 }t^3t)dt\]
 one year ago

nubeerBest ResponseYou've already chosen the best response.0
Hint. \[\int\limits_{?}^{?} t ^{4} =\frac{ t ^{4+1} }{ 4+1}\]
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
I honestly don't even know how to solve or begin to solve for it.. can you help me step by step? I have 7 more problems like this and I'd like to do them all myself.. But I need help solving and the steps to do so.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
are you familiar with the general formula of integration?
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
I'm familiar with... \[\int\limits_{a}^{b} f(x)dx=F(x)_{a}^{b} = F(b)F(a)\]
 one year ago

nubeerBest ResponseYou've already chosen the best response.0
ya this is done when we apply the limits but do you know how we do integration?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
the general formula for integration of \(\int x^n dx = \frac{x^n+1}{n+1} +C\)
 one year ago

winterfezBest ResponseYou've already chosen the best response.0
dw:1355140890023:dw
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
@winterfez i believe that's \(\left[ \frac{1}{2} \frac{t^5}{5}+\frac{1}{4} \frac{t^4}{4} \frac{t^2}{2} \right]^0_{2}\)
 one year ago

winterfezBest ResponseYou've already chosen the best response.0
\[(\frac{ 1 }{ 2 }\frac{ 0 }{ 5 }+\frac{ 1 }{ 4 }\frac{ 0^{4} }{ 4 }\frac{ 0 }{ 2 })(\frac{ 1 }{ 2 }\frac{ (2)^5 }{ 5 }+\frac{ 1 }{ 4 }\frac{ (2)^4 }{ 4 }\frac{ (2)^{2} }{ 2 })\]
 one year ago

winterfezBest ResponseYou've already chosen the best response.0
now use your calculator to punch in those suckers
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
can you explain the [...]_{2}^{0}
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
∫abf(x)dx=F(x)ba=F(b)−F(a) <this is why.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
from your original post up there.
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
ohhh so i do apply that.. I just missed a step.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
yup :) i think you've got it.
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
thank you guys! (: you're amazing!
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
I got 21/5.. does that seem right @Shadowys
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
err... let me recheck my work.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
sorry, my mistake. i typed wrong. lol no neg.
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
oh okay (: is that the answer though? because what happens with the .... +C?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
well. that's for indefinite integrals because you don't know where is the limit. the C is gone when it is definite.
 one year ago

monroe17Best ResponseYou've already chosen the best response.0
oh okay (: so 21/5 it is?
 one year ago
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