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HorseCrazyGirlForever
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\[7x + 2(3-x) = x - (3^{2} - 2^{3} ) \]
your first job is to compute \(3^3-2^3\) what is that number?
it is really \(3^2-2^3\) or is it \(3^2-2^2\) ?
the second one is \(3^2-2^2=9-4=5\) but if it is \(3^2-2^3\) then you get \[3^2-2^3=9-8=1\]
we need to know which one, otherwise we cannot complete the problem correctly if we put the wrong number down, everything will be wrong from there on in
How will we know which one?
does it read \[3^2-2^3\] with the exponent of 3 for the 2 or does it read \[3^2-2^2\] with both exponents 2