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yrelhan4 Group Title

how is log[x+ {(1+x^2)^1/2}] an odd function?

  • 2 years ago
  • 2 years ago

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  1. satellite73 Group Title
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    seems unlikely to me

    • 2 years ago
  2. satellite73 Group Title
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    for example \(f(1)=1+\sqrt{2}\) and \(f(-1)=-1+\sqrt{2}\) so it is not odd

    • 2 years ago
  3. yrelhan4 Group Title
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    i am sorry. just corrected the question.

    • 2 years ago
  4. satellite73 Group Title
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    ok now it is odd

    • 2 years ago
  5. yrelhan4 Group Title
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    @satellite73 how? i put -x in place of x? log[-x+ {(1+x^2)^1/2}]. thats what i get.

    • 2 years ago
  6. RajshikharGupta Group Title
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    [-x+ {(1+x^2)^1/2}]*[x+ {(1+x^2)^1/2}]=1 hope it is enough hint

    • 2 years ago
  7. satellite73 Group Title
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    yeah i did that too and it didn't help maybe multiply rationalize the numerator inside the log

    • 2 years ago
  8. RajshikharGupta Group Title
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    hey mann this is done

    • 2 years ago
  9. satellite73 Group Title
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    i like @RajshikharGupta solution more than mine

    • 2 years ago
  10. RajshikharGupta Group Title
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    thank u

    • 2 years ago
  11. yrelhan4 Group Title
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    thank you!

    • 2 years ago
  12. RajshikharGupta Group Title
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    2*thank u

    • 2 years ago
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