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yrelhan4
 2 years ago
how is log[x+ {(1+x^2)^1/2}] an odd function?
yrelhan4
 2 years ago
how is log[x+ {(1+x^2)^1/2}] an odd function?

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0seems unlikely to me

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0for example \(f(1)=1+\sqrt{2}\) and \(f(1)=1+\sqrt{2}\) so it is not odd

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0i am sorry. just corrected the question.

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0@satellite73 how? i put x in place of x? log[x+ {(1+x^2)^1/2}]. thats what i get.

RajshikharGupta
 2 years ago
Best ResponseYou've already chosen the best response.2[x+ {(1+x^2)^1/2}]*[x+ {(1+x^2)^1/2}]=1 hope it is enough hint

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0yeah i did that too and it didn't help maybe multiply rationalize the numerator inside the log

RajshikharGupta
 2 years ago
Best ResponseYou've already chosen the best response.2hey mann this is done

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0i like @RajshikharGupta solution more than mine
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