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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
seems unlikely to me
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
for example \(f(1)=1+\sqrt{2}\) and \(f(1)=1+\sqrt{2}\) so it is not odd
 2 years ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
i am sorry. just corrected the question.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
ok now it is odd
 2 years ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 how? i put x in place of x? log[x+ {(1+x^2)^1/2}]. thats what i get.
 2 years ago

RajshikharGupta Group TitleBest ResponseYou've already chosen the best response.2
[x+ {(1+x^2)^1/2}]*[x+ {(1+x^2)^1/2}]=1 hope it is enough hint
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
yeah i did that too and it didn't help maybe multiply rationalize the numerator inside the log
 2 years ago

RajshikharGupta Group TitleBest ResponseYou've already chosen the best response.2
hey mann this is done
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i like @RajshikharGupta solution more than mine
 2 years ago

RajshikharGupta Group TitleBest ResponseYou've already chosen the best response.2
thank u
 2 years ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
thank you!
 2 years ago

RajshikharGupta Group TitleBest ResponseYou've already chosen the best response.2
2*thank u
 2 years ago
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