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how is log[x+ {(1+x^2)^1/2}] an odd function?

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seems unlikely to me
for example \(f(1)=1+\sqrt{2}\) and \(f(-1)=-1+\sqrt{2}\) so it is not odd
i am sorry. just corrected the question.

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Other answers:

ok now it is odd
@satellite73 how? i put -x in place of x? log[-x+ {(1+x^2)^1/2}]. thats what i get.
[-x+ {(1+x^2)^1/2}]*[x+ {(1+x^2)^1/2}]=1 hope it is enough hint
yeah i did that too and it didn't help maybe multiply rationalize the numerator inside the log
hey mann this is done
i like @RajshikharGupta solution more than mine
thank u
thank you!
2*thank u

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