yrelhan4
  • yrelhan4
how is log[x+ {(1+x^2)^1/2}] an odd function?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
seems unlikely to me
anonymous
  • anonymous
for example \(f(1)=1+\sqrt{2}\) and \(f(-1)=-1+\sqrt{2}\) so it is not odd
yrelhan4
  • yrelhan4
i am sorry. just corrected the question.

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anonymous
  • anonymous
ok now it is odd
yrelhan4
  • yrelhan4
@satellite73 how? i put -x in place of x? log[-x+ {(1+x^2)^1/2}]. thats what i get.
anonymous
  • anonymous
[-x+ {(1+x^2)^1/2}]*[x+ {(1+x^2)^1/2}]=1 hope it is enough hint
anonymous
  • anonymous
yeah i did that too and it didn't help maybe multiply rationalize the numerator inside the log
anonymous
  • anonymous
hey mann this is done
anonymous
  • anonymous
i like @RajshikharGupta solution more than mine
anonymous
  • anonymous
thank u
yrelhan4
  • yrelhan4
thank you!
anonymous
  • anonymous
2*thank u

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