yrelhan4
how is log[x+ {(1+x^2)^1/2}] an odd function?



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anonymous
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seems unlikely to me

anonymous
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for example \(f(1)=1+\sqrt{2}\) and \(f(1)=1+\sqrt{2}\) so it is not odd

yrelhan4
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i am sorry. just corrected the question.

anonymous
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ok now it is odd

yrelhan4
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@satellite73 how? i put x in place of x? log[x+ {(1+x^2)^1/2}]. thats what i get.

RajshikharGupta
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[x+ {(1+x^2)^1/2}]*[x+ {(1+x^2)^1/2}]=1
hope it is enough hint

anonymous
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yeah i did that too and it didn't help
maybe multiply rationalize the numerator inside the log

RajshikharGupta
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hey mann this is done

anonymous
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i like @RajshikharGupta solution more than mine

RajshikharGupta
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thank u

yrelhan4
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thank you!

RajshikharGupta
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2*thank u