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AamirKhandayBest ResponseYou've already chosen the best response.0
it is a factor which when multiplied both sides to a linear ODE becomes an exact differential
 11 months ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[y'+p(x)y=q(x)\\\qquad\qquad\mu(x)=e^{\int p(x)\mathrm dx}\\\big(\mu (x)y(x)\big)'= \mu (x)q(x)\]
 10 months ago
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