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morganalana17

  • 3 years ago

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  1. UnkleRhaukus
    • 3 years ago
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    for \(ax^2+bx+c=0\) the discriminant is \(\Delta = b^2-4ac\)

  2. UnkleRhaukus
    • 3 years ago
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    when Δ is positive there are two real solutions when Δ is zero there is one real solution when Δ is negative there are two complex solutions (a complex number has a real and an imaginary part )

  3. UnkleRhaukus
    • 3 years ago
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    if you had to find these solutions, then you would use quadratic formula \[\frac{-b\pm\sqrt \Delta}{2a}\] i guess your solutions would be purely imaginary only when \(b=0\)

  4. kaitie45
    • 3 years ago
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    Are you a connections student? @morganlana17

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