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morganalana17
saw
for \(ax^2+bx+c=0\) the discriminant is \(\Delta = b^2-4ac\)
when Δ is positive there are two real solutions when Δ is zero there is one real solution when Δ is negative there are two complex solutions (a complex number has a real and an imaginary part )
if you had to find these solutions, then you would use quadratic formula \[\frac{-b\pm\sqrt \Delta}{2a}\] i guess your solutions would be purely imaginary only when \(b=0\)
Are you a connections student? @morganlana17