Mr.Niceguy420
Find the slope of the line passing through (11, -2) and (2, -2).
A. 4/9
B. 9
C. 0
D. Undefined
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UnkleRhaukus
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\[(x_1,y_1),\qquad (x_2,y_2)\]
the slope is the RISE / RUN
Rise is \(y_2-y_1\)
Run is \(x_2-x_1\)
Mr.Niceguy420
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whats the answer
UnkleRhaukus
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you tell me ,
Mr.Niceguy420
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idk a
UnkleRhaukus
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have you found the rise ?
UnkleRhaukus
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in this case the rise is \[(-2)-(-2)\]
UnkleRhaukus
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and the run is \((2)-(11)\)
Mr.Niceguy420
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ok
UnkleRhaukus
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maybe a diagram could help
Mr.Niceguy420
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yea
UnkleRhaukus
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|dw:1355157126069:dw|
UnkleRhaukus
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|dw:1355157200120:dw|
UnkleRhaukus
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|dw:1355157236891:dw|
Mr.Niceguy420
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k
UnkleRhaukus
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notice how there is no rise ?
Mr.Niceguy420
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yes
UnkleRhaukus
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remembering that the slope \(m\) is rise over run
\[m=\frac{0}{9}=\]
Mr.Niceguy420
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ok
Mr.Niceguy420
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ok thanks
Bladerunner1122
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Mr.Niceguy420 the idea here is to learn. After all, if you find a question like this in the future (which you will) then you need to know how to do it yourself.
Bladerunner1122
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...
UnkleRhaukus
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you may have came to the wrong place Mr.Niceguy420
UnkleRhaukus
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what are you going to do in exam?
UnkleRhaukus
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wont get through school that way
Bladerunner1122
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Just so you know. I'm in Calc now and this stuff is still coming back. Mr.Niceguy420, cheating ultimately just hurts yourself.
Mr.Niceguy420
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im not cheating im using resources
Bladerunner1122
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Using your resources during a test is cheating unless it's open computer open book.
Bladerunner1122
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(Unless your brain is the resource ;) )
Mr.Niceguy420
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well peace
\]