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Solve the following system of equations by linear combination:
2d + e = 8
d – e = 4
A.
The solution is (5, –2).
B.
The solution is (4, 0).
C.
There is no solution.
D.
There are an infinite number of solutions.
 one year ago
 one year ago
Solve the following system of equations by linear combination: 2d + e = 8 d – e = 4 A. The solution is (5, –2). B. The solution is (4, 0). C. There is no solution. D. There are an infinite number of solutions.
 one year ago
 one year ago

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DanL33Best ResponseYou've already chosen the best response.1
Answer is B 2D+E=8 DE=4 D=4+E substitute it into first equation 2(4+E)+E=8 expand brackets 8+2E+E=8 3E=88 3E=0 E=0 substitute into original equation D0=4 D=4 (4,0)
 one year ago
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