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anonymous
 3 years ago
a^2+14a51=0
anonymous
 3 years ago
a^2+14a51=0

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mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know how to factor the left side?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0like add 51 on both sides

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0No, you need to write the left side as the product of two quantities.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0Since you have three terms, and one of them has a squared variable, follow these factoring rules: 1. First, try to factor a common factor out. In this case, 1, 14 and 51 have no common factor so there's no common factor to take out. 2. Set up two sets of parentheses: (a )(a )

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0Now you are looking for two numbers that when you multiply together you get 51, and when you add together you get 14.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0Can you think of two such numbers?

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0Right, but since the product needs to be NEGATIVE 51, and the sum +14, you need +17 and 3. 17 and + 3 will not work because although their product is 51, their sum is 14, not +14.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, so now you know the numbers are 3 and 17. Just place them inside the two parentheses like this: (a  3)(x + 17) = 0

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0Now the left side is factored.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0The next step is the following: You have a product whose result is zero. How can you get a zero as the result of the multiplication of two numbers?

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0The product that is zero is (a + 17) times (a  3). The only way that product can be zero is if one of the factors is zero. Now you need to see what values of a make these factors zero, so you write: a  3 = 0 or a + 17 = 0 Solve these simple equations and you get: a = 3 or a = 17

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so i can do this on every problem to get dis answer

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0This is the method for problems of the type: x^2 + ax + c = 0 where a and b are numbers, and x is the variable. For example: x^2  x  2 = 0 y^2  y  12 = 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok x^2+6x+8=0 answer is 2,4

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.0(x + 4)(x + 2) = 0 x + 4 = 0 or x + 2 = 0 x = 4 or x = 2 You are correct.
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