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zammett.damali Group TitleBest ResponseYou've already chosen the best response.0
how to work it out
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Do you know how to factor the left side?
 one year ago

zammett.damali Group TitleBest ResponseYou've already chosen the best response.0
like add 51 on both sides
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
No, you need to write the left side as the product of two quantities.
 one year ago

zammett.damali Group TitleBest ResponseYou've already chosen the best response.0
how
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Since you have three terms, and one of them has a squared variable, follow these factoring rules: 1. First, try to factor a common factor out. In this case, 1, 14 and 51 have no common factor so there's no common factor to take out. 2. Set up two sets of parentheses: (a )(a )
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Now you are looking for two numbers that when you multiply together you get 51, and when you add together you get 14.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Can you think of two such numbers?
 one year ago

zammett.damali Group TitleBest ResponseYou've already chosen the best response.0
17 and 3
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Right, but since the product needs to be NEGATIVE 51, and the sum +14, you need +17 and 3. 17 and + 3 will not work because although their product is 51, their sum is 14, not +14.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Ok, so now you know the numbers are 3 and 17. Just place them inside the two parentheses like this: (a  3)(x + 17) = 0
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
Now the left side is factored.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
The next step is the following: You have a product whose result is zero. How can you get a zero as the result of the multiplication of two numbers?
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
The product that is zero is (a + 17) times (a  3). The only way that product can be zero is if one of the factors is zero. Now you need to see what values of a make these factors zero, so you write: a  3 = 0 or a + 17 = 0 Solve these simple equations and you get: a = 3 or a = 17
 one year ago

zammett.damali Group TitleBest ResponseYou've already chosen the best response.0
so i can do this on every problem to get dis answer
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
This is the method for problems of the type: x^2 + ax + c = 0 where a and b are numbers, and x is the variable. For example: x^2  x  2 = 0 y^2  y  12 = 0
 one year ago

zammett.damali Group TitleBest ResponseYou've already chosen the best response.0
ok x^2+6x+8=0 answer is 2,4
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
(x + 4)(x + 2) = 0 x + 4 = 0 or x + 2 = 0 x = 4 or x = 2 You are correct.
 one year ago

zammett.damali Group TitleBest ResponseYou've already chosen the best response.0
ok i got it thanks
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
wlcm
 one year ago
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