anonymous
  • anonymous
Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the function f). k = 2; f(x) = 5x4 + 4x3 - 2x2 + 2x + 4; Upper bound?
Mathematics
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schrodinger
  • schrodinger
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anonymous
  • anonymous
yes correct?
anonymous
  • anonymous
@ZeHanz
ZeHanz
  • ZeHanz
If I get your question right, you do need to divide f(x) by (x-2). This goes as follows: 2 [ 5 4 -2 2 4 ] 10 28 52 108 ---------------------+ 5 14 26 54 112 <-- remainder

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anonymous
  • anonymous
so is it lower or upper level?
anonymous
  • anonymous
**bound
anonymous
  • anonymous
@zordoloom
ZeHanz
  • ZeHanz
What do you mean: an upper bound or lower bound for zeros?
anonymous
  • anonymous
i believe so
anonymous
  • anonymous
It seems like it's lower bound. Take a look at this description of bounds: Upper and Lower Bounds (http://people.richland.edu/james/lecture/m116/polynomials/zeros.html) If you have a polynomial with real coefficients and a positive leading coefficient, then ... Upper Bound If synthetic division is performed by dividing by x-k, where k>0, and all the signs in the bottom row of the synthetic division are non-negative, then x=k is an upper bound (nothing is larger) for the zeros of the polynomial. Lower Bound If synthetic division is performed by dividing by x-k, where k<0, and the signs in the bottom row of the synthetic division alternate (between non-negative and non-positive), then x=k is a lower bound (nothing is smaller) for the zeros of the polynomial. The zero in the bottom row may be considered positive or negative as needed.
ZeHanz
  • ZeHanz
f(2) = 112, there are no real zeros, see attached graph
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anonymous
  • anonymous
ohh ok thank u
ZeHanz
  • ZeHanz
Thanks, zordoloom, I didn't know that!

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