Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the function f).
k = 2; f(x) = 5x4 + 4x3 - 2x2 + 2x + 4; Upper bound?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
If I get your question right, you do need to divide f(x) by (x-2).
This goes as follows:
2 [ 5 4 -2 2 4 ]
10 28 52 108
5 14 26 54 112 <-- remainder
Not the answer you are looking for? Search for more explanations.
so is it lower or upper level?
What do you mean: an upper bound or lower bound for zeros?
i believe so
It seems like it's lower bound. Take a look at this description of bounds:
Upper and Lower Bounds
If you have a polynomial with real coefficients and a positive leading coefficient, then ...
If synthetic division is performed by dividing by x-k, where k>0, and all the signs in the bottom row of the synthetic division are non-negative, then x=k is an upper bound (nothing is larger) for the zeros of the polynomial.
If synthetic division is performed by dividing by x-k, where k<0, and the signs in the bottom row of the synthetic division alternate (between non-negative and non-positive), then x=k is a lower bound (nothing is smaller) for the zeros of the polynomial.
The zero in the bottom row may be considered positive or negative as needed.
f(2) = 112, there are no real zeros, see attached graph