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mhs2014

  • 3 years ago

how would you do 3X+5y=0 x-4y=0

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  1. CalebBeavers
    • 3 years ago
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    Is this a system of equations?

  2. mhs2014
    • 3 years ago
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    its substitution method

  3. katie1995
    • 3 years ago
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    x-4y=0 +4y +4y x=4y 3(4y)+5y=0 12y+5y=0 17y=0 divide each side by 17 y=0

  4. katie1995
    • 3 years ago
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    x=4y x=4(0) x=0

  5. mhs2014
    • 3 years ago
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    thank you

  6. mhs2014
    • 3 years ago
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    could you help me with more questions??

  7. mhs2014
    • 3 years ago
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    4k+m=9 3k-4m=2

  8. katie1995
    • 3 years ago
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    yep one sec

  9. katie1995
    • 3 years ago
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    4k+m=9 -4k -4k m=-4k+9 3k-4(-4k+9)=2 3k+16k-36=2 +36 +36 19k=38 divide each side by 19 k=2

  10. katie1995
    • 3 years ago
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    4(2)+m=9 8+m=9 -8 -8 m=1

  11. katie1995
    • 3 years ago
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    Do you understand what I did to get those answers or would you like me to explain?

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