mhs2014
how would you do
3X+5y=0
x4y=0



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CalebBeavers
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Is this a system of equations?

mhs2014
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its substitution method

katie1995
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x4y=0
+4y +4y
x=4y
3(4y)+5y=0
12y+5y=0
17y=0
divide each side by 17
y=0

katie1995
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x=4y
x=4(0)
x=0

mhs2014
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thank you

mhs2014
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could you help me with more questions??

mhs2014
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4k+m=9
3k4m=2

katie1995
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yep one sec

katie1995
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4k+m=9
4k 4k
m=4k+9
3k4(4k+9)=2
3k+16k36=2
+36 +36
19k=38
divide each side by 19
k=2

katie1995
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4(2)+m=9
8+m=9
8 8
m=1

katie1995
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Do you understand what I did to get those answers or would you like me to explain?