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how would you do 3X+5y=0 x-4y=0

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Is this a system of equations?
its substitution method
x-4y=0 +4y +4y x=4y 3(4y)+5y=0 12y+5y=0 17y=0 divide each side by 17 y=0

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Other answers:

x=4y x=4(0) x=0
thank you
could you help me with more questions??
4k+m=9 3k-4m=2
yep one sec
4k+m=9 -4k -4k m=-4k+9 3k-4(-4k+9)=2 3k+16k-36=2 +36 +36 19k=38 divide each side by 19 k=2
4(2)+m=9 8+m=9 -8 -8 m=1
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