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Mathhelp346

  • 3 years ago

PLEASEE HELP PLEASE!!!: 1. (-1+i √5)^2 2. (2-3i √2)^2

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  1. TBMonkey
    • 3 years ago
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    are they supposed to be equal?

  2. Mathhelp346
    • 3 years ago
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    No, they're two seperate problems

  3. Mathhelp346
    • 3 years ago
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    Sorry for the confusion

  4. TBMonkey
    • 3 years ago
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    no problem hang on a sec kk?

  5. Mathhelp346
    • 3 years ago
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    Ok, thanks

  6. TBMonkey
    • 3 years ago
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    the first one should be i*4.84 the second should be i*1.96

  7. Mathhelp346
    • 3 years ago
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    How did you figure those out?

  8. Mathhelp346
    • 3 years ago
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    I checked the answers at the back of my textbook and it says -4-2i√5. Is that the same thing?

  9. TBMonkey
    • 3 years ago
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    yes but more complicated(:

  10. Mathhelp346
    • 3 years ago
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    Oh, ok. But how did you get those answers anyways?

  11. TBMonkey
    • 3 years ago
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    step by step lol your book should tell you

  12. Mathhelp346
    • 3 years ago
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    It doesn't have an example on this type. I don't know how to solve it with a square root.

  13. TBMonkey
    • 3 years ago
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    What?

  14. Mathhelp346
    • 3 years ago
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    Can you show me how you solved it step by step?

  15. anikay
    • 3 years ago
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    I can!

  16. Mathhelp346
    • 3 years ago
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    Ok :o

  17. anikay
    • 3 years ago
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    only cuz of your adorable pikachus though :D

  18. Mathhelp346
    • 3 years ago
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    xD Thank you

  19. anikay
    • 3 years ago
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    do you know what \[i^2 \] is?

  20. Mathhelp346
    • 3 years ago
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    yes -1

  21. anikay
    • 3 years ago
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    ok, so..... \[(-1+i+\sqrt{5})^2\] that's it?

  22. Mathhelp346
    • 3 years ago
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    That's it?

  23. anikay
    • 3 years ago
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    is that the problem in your book?

  24. Mathhelp346
    • 3 years ago
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    \[(-1+i \sqrt{5})^{2}\]

  25. Mathhelp346
    • 3 years ago
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    It's that

  26. anikay
    • 3 years ago
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    ok thanks

  27. anikay
    • 3 years ago
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    so we square everything inside the parentheses. to get -4

  28. anikay
    • 3 years ago
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    because -1^2 = 1 and i^2 = -1 and sqrt(5)^2 = 5 right?

  29. Mathhelp346
    • 3 years ago
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    Yeah

  30. anikay
    • 3 years ago
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    so the answer should be -4.....imo

  31. anikay
    • 3 years ago
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    is there something about the problem I'm missing?

  32. Mathhelp346
    • 3 years ago
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    But the answers in my textbook say it's -4-2i√5. Or is your answer and the textbook's the same thing?

  33. anikay
    • 3 years ago
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    they aren't

  34. anikay
    • 3 years ago
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    mine is simplifying the expression..... is that what your book is asking for

  35. Mathhelp346
    • 3 years ago
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    The textbook says multiply

  36. anikay
    • 3 years ago
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    ....omg I'm so sorry

  37. anikay
    • 3 years ago
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    *facepalm* I'm tired. gonna head to bed after I finish helping you

  38. anikay
    • 3 years ago
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    \[(-1+i \sqrt{5})(-1+i \sqrt{5})\]

  39. anikay
    • 3 years ago
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    foil

  40. Mathhelp346
    • 3 years ago
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    1+i√5^2?

  41. anikay
    • 3 years ago
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    ok, F.O.I.L. Front, Outside, Inside, Last

  42. anikay
    • 3 years ago
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    so first we multiply -1 by -1

  43. anikay
    • 3 years ago
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    ok we get 1 next we mutiply \[-1*i \sqrt{5}\]

  44. anikay
    • 3 years ago
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    then we do the same thing again for the inside terms

  45. anikay
    • 3 years ago
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    then the last, which is \[i \sqrt{5}*i \sqrt{5}\]

  46. anikay
    • 3 years ago
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    so all together, we get\[1- i \sqrt{5} - i \sqrt{5} - 5\] which simplifies to \[-4 -2i \sqrt{5}\]

  47. Mathhelp346
    • 3 years ago
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    oh ok thank you

  48. anikay
    • 3 years ago
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    so F.O.I.L, gotta remember that :P

  49. Mathhelp346
    • 3 years ago
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    Ok ^-^ Good night

  50. anikay
    • 3 years ago
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    here's a picture, just for good measure |dw:1355203674722:dw|

  51. anikay
    • 3 years ago
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    night

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