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describe the motion of a point on a wheel that has a centre 4m off the ground, has radius of 15 cm, makes a full rotation every 10 seconds and starts at its highest point. use y=asink(t-b)+c model or cosine function.

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c=4 and a=.15 ... is that part clear?
a=15 not .15..
false. :) continuing... \[f=\frac{ 1 }{10}\] \[\omega = 2 \pi f\] \[w= \frac{ \pi }{ 5 }\]

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Other answers:

agree so far?
yes i got that part
so the phase...
we want it to be at the highest point when t=0... sin =1 when theta = pi/2 pi/5 *(t-b) = pi/2 pi/5(-b) = pi/2 b= 5/2
\[y = .15 \sin (\frac{ \pi }{ 5} (t+\frac{ 5 }{2})) +4\]
would it be appropriate to keep(t-b) it at pi/5 *(t) + pi/2 ?
you can... that's not the form they ask you to use though...
whoops, should say b=-5/2 up there... typo
oh okay. & also for cosine model it would just be \[y=.15\cos(\frac{ \pi }{ 5 }t) +4\] right??
why would it be -5/2 and not 5/2 ? :S
why is b= -5/2? is that what you're asking?
OH WAIT.. nvm.. you were referring to your reply before the equation. nvm. lol

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