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describe the motion of a point on a wheel that has a centre 4m off the ground, has radius of 15 cm, makes a full rotation every 10 seconds and starts at its highest point. use y=asink(tb)+c model or cosine function.
 one year ago
 one year ago
describe the motion of a point on a wheel that has a centre 4m off the ground, has radius of 15 cm, makes a full rotation every 10 seconds and starts at its highest point. use y=asink(tb)+c model or cosine function.
 one year ago
 one year ago

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Algebraic!Best ResponseYou've already chosen the best response.1
c=4 and a=.15 ... is that part clear?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
false. :) continuing... \[f=\frac{ 1 }{10}\] \[\omega = 2 \pi f\] \[w= \frac{ \pi }{ 5 }\]
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
yes i got that part
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
we want it to be at the highest point when t=0... sin =1 when theta = pi/2 pi/5 *(tb) = pi/2 pi/5(b) = pi/2 b= 5/2
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
\[y = .15 \sin (\frac{ \pi }{ 5} (t+\frac{ 5 }{2})) +4\]
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
would it be appropriate to keep(tb) it at pi/5 *(t) + pi/2 ?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
you can... that's not the form they ask you to use though...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
whoops, should say b=5/2 up there... typo
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
oh okay. & also for cosine model it would just be \[y=.15\cos(\frac{ \pi }{ 5 }t) +4\] right??
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
why would it be 5/2 and not 5/2 ? :S
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
why is b= 5/2? is that what you're asking?
 one year ago

alexeis_nicoleBest ResponseYou've already chosen the best response.0
OH WAIT.. nvm.. you were referring to your reply before the equation. nvm. lol
 one year ago
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