alexeis_nicole
describe the motion of a point on a wheel that has a centre 4m off the ground, has radius of 15 cm, makes a full rotation every 10 seconds and starts at its highest point. use y=asink(t-b)+c model or cosine function.
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c=4 and a=.15 ... is that part clear?
alexeis_nicole
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a=15 not .15..
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false.
:)
continuing...
\[f=\frac{ 1 }{10}\]
\[\omega = 2 \pi f\]
\[w= \frac{ \pi }{ 5 }\]
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agree so far?
alexeis_nicole
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yes i got that part
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so the phase...
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we want it to be at the highest point when t=0...
sin =1 when theta = pi/2
pi/5 *(t-b) = pi/2
pi/5(-b) = pi/2
b= 5/2
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\[y = .15 \sin (\frac{ \pi }{ 5} (t+\frac{ 5 }{2})) +4\]
alexeis_nicole
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would it be appropriate to keep(t-b) it at pi/5 *(t) + pi/2 ?
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you can... that's not the form they ask you to use though...
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whoops, should say b=-5/2 up there... typo
alexeis_nicole
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oh okay.
& also for cosine model it would just be \[y=.15\cos(\frac{ \pi }{ 5 }t) +4\]
right??
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yes
alexeis_nicole
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why would it be -5/2 and not 5/2 ? :S
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why is b= -5/2? is that what you're asking?
alexeis_nicole
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OH WAIT.. nvm.. you were referring to your reply before the equation. nvm. lol
alexeis_nicole
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thanks!
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sure:)