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c=4 and a=.15 ... is that part clear?

a=15 not .15..

false.
:)
continuing...
\[f=\frac{ 1 }{10}\]
\[\omega = 2 \pi f\]
\[w= \frac{ \pi }{ 5 }\]

agree so far?

yes i got that part

so the phase...

\[y = .15 \sin (\frac{ \pi }{ 5} (t+\frac{ 5 }{2})) +4\]

would it be appropriate to keep(t-b) it at pi/5 *(t) + pi/2 ?

you can... that's not the form they ask you to use though...

whoops, should say b=-5/2 up there... typo

oh okay.
& also for cosine model it would just be \[y=.15\cos(\frac{ \pi }{ 5 }t) +4\]
right??

yes

why would it be -5/2 and not 5/2 ? :S

why is b= -5/2? is that what you're asking?

OH WAIT.. nvm.. you were referring to your reply before the equation. nvm. lol

thanks!

sure:)