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KonradZuse

  • 2 years ago

In 1965, about 44% of the U.S. adult population had never smoked cigarettes. A national health survey of 1205 U.S. adults (presumably selected randomly) during 2006 revealed that 615 had never smoked cigarettes. Reference: Ref 18-5 Suppose you wished to test whether there has been a change since 1965 in the proportion of U.S. adults that have never smoked cigarettes. Which of the following are the appropriate hypotheses? A. H0: p = 0.44, Ha: p > 0.44 B. H0: p = 0.51, Ha: p 0.51 C. H0: p = 0.44, Ha: p 0.44 D. H0: = 0.44, Ha: 0.44 The P-value of the test of hypotheses is A. greater than 0.10. B. between 0.05 and 0.10. C. between .01 and 0.05. D. below 0.01.

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  1. KonradZuse
    • 2 years ago
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    @jim_thompson5910

  2. jim_thompson5910
    • 2 years ago
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    what did you get for the first part

  3. KonradZuse
    • 2 years ago
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    I forgot to mention that there was a misprint when I pasted.. B is not equal, same with C, and then there is a p ^ for both of D's answers... I think it's B....

  4. jim_thompson5910
    • 2 years ago
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    D is out because you're not testing p^, you're testing p

  5. jim_thompson5910
    • 2 years ago
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    how are you getting 51% ? the given percentage is 44%

  6. jim_thompson5910
    • 2 years ago
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    oh i see, you divided 615/1205 = 0.51, but that's p^ and NOT p

  7. KonradZuse
    • 2 years ago
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    I meant C?

  8. jim_thompson5910
    • 2 years ago
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    you did eh? lol yeah C is correct

  9. KonradZuse
    • 2 years ago
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    Haha I glanced over them didn't realize that there were 2 of the same haha... I wanted the one that was not equal :D.

  10. KonradZuse
    • 2 years ago
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    Would the next part be B?

  11. jim_thompson5910
    • 2 years ago
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    you first need to find the test statistic

  12. KonradZuse
    • 2 years ago
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    hmm....

  13. jim_thompson5910
    • 2 years ago
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    use the formula z = (m - p)/(sqrt(pq/n)) where m is the test statistic and q = 1-p z = (m - p)/(sqrt(pq/n)) z = (0.51037 - 0.44)/(sqrt(0.44*0.56/1205)) z = 4.92108 So the test statistic is z = 4.92108

  14. jim_thompson5910
    • 2 years ago
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    now you need to find P(z > 4.92108) and double this result

  15. jim_thompson5910
    • 2 years ago
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    you can get away without even using a calculator though because notice how far z = 4.92108 is from z = 0

  16. KonradZuse
    • 2 years ago
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    mhm,.

  17. jim_thompson5910
    • 2 years ago
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    so what's the p value

  18. KonradZuse
    • 2 years ago
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    not b hmm? A?

  19. jim_thompson5910
    • 2 years ago
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    what did you get for the p-value, which numeric value did you get

  20. KonradZuse
    • 2 years ago
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    not sure....

  21. jim_thompson5910
    • 2 years ago
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    calculate P(z > 4.92108), what do you get

  22. KonradZuse
    • 2 years ago
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    How do we calculate that again without the table?

  23. jim_thompson5910
    • 2 years ago
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    type normalcdf(4.92108, 10) into wolfram alpha

  24. jim_thompson5910
    • 2 years ago
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    or you can use a TI calculator to do the same thing

  25. KonradZuse
    • 2 years ago
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    hm.... Now the le end poin is almos 5, but the oher bnumbers are super tiny

  26. jim_thompson5910
    • 2 years ago
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    so that means what

  27. KonradZuse
    • 2 years ago
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    A or D.

  28. jim_thompson5910
    • 2 years ago
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    why A

  29. KonradZuse
    • 2 years ago
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    Well like I said I wasn't sre if it was the 5 or tiny #'s.. So D then :)

  30. jim_thompson5910
    • 2 years ago
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    well the p value is very very small, so it has to be less than 0.01

  31. jim_thompson5910
    • 2 years ago
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    the p value is the 4th value down

  32. jim_thompson5910
    • 2 years ago
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    well you double it first, but still, it's very small

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