## KonradZuse 2 years ago In 1965, about 44% of the U.S. adult population had never smoked cigarettes. A national health survey of 1205 U.S. adults (presumably selected randomly) during 2006 revealed that 615 had never smoked cigarettes. Reference: Ref 18-5 Suppose you wished to test whether there has been a change since 1965 in the proportion of U.S. adults that have never smoked cigarettes. Which of the following are the appropriate hypotheses? A. H0: p = 0.44, Ha: p > 0.44 B. H0: p = 0.51, Ha: p 0.51 C. H0: p = 0.44, Ha: p 0.44 D. H0: = 0.44, Ha: 0.44 The P-value of the test of hypotheses is A. greater than 0.10. B. between 0.05 and 0.10. C. between .01 and 0.05. D. below 0.01.

@jim_thompson5910

2. jim_thompson5910

what did you get for the first part

I forgot to mention that there was a misprint when I pasted.. B is not equal, same with C, and then there is a p ^ for both of D's answers... I think it's B....

4. jim_thompson5910

D is out because you're not testing p^, you're testing p

5. jim_thompson5910

how are you getting 51% ? the given percentage is 44%

6. jim_thompson5910

oh i see, you divided 615/1205 = 0.51, but that's p^ and NOT p

I meant C?

8. jim_thompson5910

you did eh? lol yeah C is correct

Haha I glanced over them didn't realize that there were 2 of the same haha... I wanted the one that was not equal :D.

Would the next part be B?

11. jim_thompson5910

you first need to find the test statistic

hmm....

13. jim_thompson5910

use the formula z = (m - p)/(sqrt(pq/n)) where m is the test statistic and q = 1-p z = (m - p)/(sqrt(pq/n)) z = (0.51037 - 0.44)/(sqrt(0.44*0.56/1205)) z = 4.92108 So the test statistic is z = 4.92108

14. jim_thompson5910

now you need to find P(z > 4.92108) and double this result

15. jim_thompson5910

you can get away without even using a calculator though because notice how far z = 4.92108 is from z = 0

mhm,.

17. jim_thompson5910

so what's the p value

not b hmm? A?

19. jim_thompson5910

what did you get for the p-value, which numeric value did you get

not sure....

21. jim_thompson5910

calculate P(z > 4.92108), what do you get

How do we calculate that again without the table?

23. jim_thompson5910

type normalcdf(4.92108, 10) into wolfram alpha

24. jim_thompson5910

or you can use a TI calculator to do the same thing

hm.... Now the le end poin is almos 5, but the oher bnumbers are super tiny

26. jim_thompson5910

so that means what

A or D.

28. jim_thompson5910

why A

Well like I said I wasn't sre if it was the 5 or tiny #'s.. So D then :)

30. jim_thompson5910

well the p value is very very small, so it has to be less than 0.01

31. jim_thompson5910

the p value is the 4th value down

32. jim_thompson5910

well you double it first, but still, it's very small