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anonymous
 3 years ago
Please help crashing for finals!
The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.
anonymous
 3 years ago
Please help crashing for finals! The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A= l*h = (4t+5)(t^6) dA/dt = d/dt (4t^7 +5t^6 )

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my teacher gave me the answer it is dA/dt=t^3(30+28t) but im not so sure as to how to do the problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats what i got when i first did the problem what you gave me just now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dA/dt=t^5(30+28t) think you have a typo there..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or in the original problem...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah you know what i was thinking that too. so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right? simply taking the derivative??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0:( no i need a definite answer because i have a final in a couple of days and i NEED to get a good score on it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0"so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right?" I have no idea what that word salad might mean... so I decline to comment on it aside from a provisional 'sure'
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