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Please help crashing for finals!
The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.
 one year ago
 one year ago
Please help crashing for finals! The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.
 one year ago
 one year ago

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Algebraic!Best ResponseYou've already chosen the best response.0
A= l*h = (4t+5)(t^6) dA/dt = d/dt (4t^7 +5t^6 )
 one year ago

lilly21Best ResponseYou've already chosen the best response.0
my teacher gave me the answer it is dA/dt=t^3(30+28t) but im not so sure as to how to do the problem
 one year ago

lilly21Best ResponseYou've already chosen the best response.0
thats what i got when i first did the problem what you gave me just now
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
dA/dt=t^5(30+28t) think you have a typo there..
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
or in the original problem...
 one year ago

lilly21Best ResponseYou've already chosen the best response.0
yeah you know what i was thinking that too. so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right? simply taking the derivative??
 one year ago

lilly21Best ResponseYou've already chosen the best response.0
:( no i need a definite answer because i have a final in a couple of days and i NEED to get a good score on it
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
"so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right?" I have no idea what that word salad might mean... so I decline to comment on it aside from a provisional 'sure'
 one year ago
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