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lilly21

  • 3 years ago

Please help crashing for finals! The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.

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  1. Algebraic!
    • 3 years ago
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    A= l*h = (4t+5)(t^6) dA/dt = d/dt (4t^7 +5t^6 )

  2. lilly21
    • 3 years ago
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    my teacher gave me the answer it is dA/dt=t^3(30+28t) but im not so sure as to how to do the problem

  3. Algebraic!
    • 3 years ago
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    aka 28t^6 +30t^5

  4. lilly21
    • 3 years ago
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    thats what i got when i first did the problem what you gave me just now

  5. Algebraic!
    • 3 years ago
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    dA/dt=t^5(30+28t) think you have a typo there..

  6. Algebraic!
    • 3 years ago
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    or in the original problem...

  7. lilly21
    • 3 years ago
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    yeah you know what i was thinking that too. so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right? simply taking the derivative??

  8. Algebraic!
    • 3 years ago
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    sure

  9. lilly21
    • 3 years ago
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    :( no i need a definite answer because i have a final in a couple of days and i NEED to get a good score on it

  10. Algebraic!
    • 3 years ago
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    "so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right?" I have no idea what that word salad might mean... so I decline to comment on it aside from a provisional 'sure'

  11. lilly21
    • 3 years ago
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    okay then thanks

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