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Please help crashing for finals! The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.

Mathematics
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A= l*h = (4t+5)(t^6) dA/dt = d/dt (4t^7 +5t^6 )
my teacher gave me the answer it is dA/dt=t^3(30+28t) but im not so sure as to how to do the problem
aka 28t^6 +30t^5

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Other answers:

thats what i got when i first did the problem what you gave me just now
dA/dt=t^5(30+28t) think you have a typo there..
or in the original problem...
yeah you know what i was thinking that too. so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right? simply taking the derivative??
sure
:( no i need a definite answer because i have a final in a couple of days and i NEED to get a good score on it
"so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right?" I have no idea what that word salad might mean... so I decline to comment on it aside from a provisional 'sure'
okay then thanks

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