Please help crashing for finals!
The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.

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A= l*h = (4t+5)(t^6)
dA/dt = d/dt (4t^7 +5t^6 )

my teacher gave me the answer it is dA/dt=t^3(30+28t) but im not so sure as to how to do the problem

aka
28t^6 +30t^5

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