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anonymous
 3 years ago
I need help solving this system of a linear equation based on the attached augmented MATRIX
anonymous
 3 years ago
I need help solving this system of a linear equation based on the attached augmented MATRIX

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355196230716:dw

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1You need to reduce it to something like this: dw:1355198633863:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeh, i watched some video chalkboard examples, but they didn't have the bigger numbers in matrix! its got me vexed...lol

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1It's a thing called "Reduced Row Echelon Form". So firstly start by making m(row)(column) m00 = 1 then m10 = 0 then m20=0 So the first colum will be 1, 0, 0

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1If you swap Row 2 with row 1 it'll put that 1 in the right place allowing you to make the rest of the column 0 easier.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how do i get 100 with that starting matrix though 3,1,2? canu show me the next couple steps on this problem?

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1I with this was easier to type on a computer =( dw:1355199296801:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so i can just change the position of rowa 1 and 2?

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1Yes, but you have to change the ENTIRE row.. Hence why they're called "Row Operations" 1) Interchange two rows. 2) Multiple a row by any nonzero number 3) Add a multiple of a row to another row.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, i find the draw pad fastest...lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think i am mentally wounded on this. just been way too long since i had to do one!! hate to ask, but my answer choices are like (1,1,0). how do i get it rest of the way to that. i don't trust myself on this one if i did get to the end!@

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if its easier to work out on ur notepad,thats ok just pass me the 3 valuessoi can get out of this section. I'm definitely going to needto go back thru the tutorialfromthe start on these matrix'?

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1Only notebook I could find nearby, sorry it's hard to read but my values are: 1, 1, 0

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1\[3x_1+x_22x_3=2\]\[3(1)+(1)2(0)=31=2\]

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1\[x_12x_2+x_3=3\]\[(1)2(1)+0=1+2=3\] \[2x_1x_23x_3=3\]\[2(1)(1)3(0)=2+1=3\] The values work in all equations therefore 1, 1, 0 is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanksfor the extra effort to show me ur work , i'mgoing to have to study that before my next test!

PhoenixFire
 3 years ago
Best ResponseYou've already chosen the best response.1No problem, when I learnt it I had lots of trouble getting it right. Just keep practicing!
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