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anonymous
 4 years ago
Find the number of different arrangements that are possible for the letters. FACTOR
anonymous
 4 years ago
Find the number of different arrangements that are possible for the letters. FACTOR

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do i use permutation, combination, i don't get it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is a brain teaser right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its in the trigonometry curriculum

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nope I have trigonometric nightmares during high school.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not for me. Biohazard

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol so you don't know how to do it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Im ultra retarded when it comes to anythign bu solving linear algebraic expressions or equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was that person once lol, just gotta put some effort in, but from what you said earlier I'm guessing your done with high school, am i right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes I am in college and the nightmare has just began...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@bunyonb It actually is math. There are six letters, none of which occur twice. The number of combinations for the letters can be found by a simple statistics formula: (x)! Where x is the number of elements that can be combined in a certain order. So, substitute 6 in for x to get: (6)! In case you're wondering the exclamation mark means factorial, which simply means that you multiply the integer by each of its preceding integers, all the way to one. So 6! = 6*5*4*3*2*1 = 720 Your answer is 720.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol, you seem like the same person as me, you don't wanna put in the effort, i could care less about math, but i still gotta do it, and your in college so its supper serious, good luck man :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@ujhk77 thats exactly what i got, just was unsure, thanks for the clarity, much appreciated :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok now that is a little better

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@life No problemo bro, I'm happy to help. :)
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