lilsis76
  • lilsis76
convert the given polar coordinates to rectangular coordinates.(10, pi/5) i know x=rcosQ y=rsinQ i guess i plug in 10 cos(pi/5)? right??
Mathematics
schrodinger
  • schrodinger
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anikay
  • anikay
oh god why >.>
lilsis76
  • lilsis76
HAHA
lilsis76
  • lilsis76
Im sorry if i am completely blank

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anikay
  • anikay
this stuff was the worst part of my junior year xD
lilsis76
  • lilsis76
HAHA, dang how old are you? i never took this in HighSchool. my highest was Algebra
anikay
  • anikay
I'm 17. and yes, to get x you plug in \[10\cos (\pi/5)\] and for y \[10\sin (\pi/5)\]
lilsis76
  • lilsis76
well i tried that x=10 cos pi/5 --> 9.99 ? y=10 sin pi/5--> .0349
anikay
  • anikay
yup I think so
lilsis76
  • lilsis76
okay, i have a question tho now. i got this question wrong and the instructor circled my pi/5 and wrote radians. isnt it in radians?
anikay
  • anikay
yes, should it be degress?
lilsis76
  • lilsis76
lol it doesnt say, but i dont know why she circledit lol. THANK YOU OH SO VERY MUCH!!!!! i really appreciate it. UGH i gotta do better on this test make up.
lilsis76
  • lilsis76
Have a goodnite!
anikay
  • anikay
i got a test make-up friday and a test tomorrow
anikay
  • anikay
Calc, is much easier imo
lilsis76
  • lilsis76
oh boy, :/ i would def. fail that. lol i hope so i have to get all the way to calc 2 i think. Well im logging off. thank you very much. Have a goodnite
anikay
  • anikay
if you ever need calc help, I'm an @ away. night
lilsis76
  • lilsis76
haha
phi
  • phi
*** well i tried that x=10 cos pi/5 --> 9.99 ? y=10 sin pi/5--> .0349 *** right idea, but you had your calculator in "degree mode" rather than "radian mode" so you are getting the wrong answer the safest way to do this is change pi/5 radians to degrees you do this by multiplying by 180/pi \[ \frac{\cancel{\pi}}{5} \text{ rads} \cdot \frac{180}{\cancel{\pi}}= \frac{180}{5}= 36ยบ \] now, with your calculator in "DEGREE MODE" do 10*cos(36)= 8.08 10*sin(36)= 5.88 your rectangular coordinates are (8.08, 5.88)
anikay
  • anikay
oh right, because theta always gives a polar answer, thanks :D

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