anonymous
  • anonymous
Again look at the picture
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
help please
anonymous
  • anonymous
anonymous
  • anonymous

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anonymous
  • anonymous
abb0t
  • abb0t
They are all polynomials. sqrt of x is the same thing as x^1/2
anonymous
  • anonymous
thank you
mathstudent55
  • mathstudent55
A, D, E, F are. Others are not. B has x in radical, and C has variables in the denominator.
abb0t
  • abb0t
Even if the variables are in the radicals, you can still express them as: \[x^{-n} \] similarly, \[\sqrt{x} = x ^{\frac{ 1 }{ 2 }}\]
abb0t
  • abb0t
in the denom*
mathstudent55
  • mathstudent55
That's not a polynomial, though. In a ploynomial, variables can only have non-negative exponents.
abb0t
  • abb0t
Oh sh*t. You're right. My bad.
mathstudent55
  • mathstudent55
np

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