A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
help me plz. again w/ this one 12+2xlessthan or equal to 6
Thank you!
anonymous
 4 years ago
help me plz. again w/ this one 12+2xlessthan or equal to 6 Thank you!

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The question is \(12+2x\le6\) and solve x...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01. subtract 12 from both sides. 2. divide both sides by 2.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.012 + 12x <= 6 (subtract 12 from each side) 12  12 + 12x <= 6  12 12x <= 6  12 12x <=  12 (divide by 12 to get x by itself) 12x/12 <=  12/12 x <=  1

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1It is better to guide the user to an answer rather than doing all the work yourself. We discourage giving out answers without letting the asker at least take some part in the analysis  the aim of this site is to teach. Please refer to our code of conduct at http://openstudy.com/codeofconduct for more information. Thank you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got negative 3  12+2x>6 12 12 2x>6 2x/2>6/2 x>3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops I wrote the problem wrong....srry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's okay!, I've got a clue from your answer! :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes . .. Thannk you so much, I also got x≤3 :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.