anonymous
  • anonymous
how about if it is fraction? wat will I do 1st? 3x/4 ≥-6 Thank you!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1. Multiply both sides by 4 2. Divide both sides by 3
anonymous
  • anonymous
Or 1. Multiply both sides by 4/3
anonymous
  • anonymous
ok, thank you

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More answers

anonymous
  • anonymous
i can't remember if it is negative when you subtract a lower positive number from a higher negative number? Help pls. Thank you!
anonymous
  • anonymous
2-3 = -1
anonymous
  • anonymous
Does it help?
anonymous
  • anonymous
yes. a big heLp.... now I don't have hesitation in my answer! Thanks
anonymous
  • anonymous
wat if negative divide by negative? is it equal to positive?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
+ve times +ve = +ve +ve times -ve = -ve -ve times -ve = +ve Same holds for division.
anonymous
  • anonymous
ahm...okay, I thought It was different rule!
anonymous
  • anonymous
I got 2 unfinished answers w/ my questions, bcoz now I'm confused which answer will i proceed, which is correct 3x/4 times 4/3 is equal to 12x/7 or 9x*16?
anonymous
  • anonymous
\[\frac{3x}{4} ≥-6\]\[\frac{4}{3}\times\frac{3x}{4} ≥-6\times \frac{4}{3}\]Simplify the left and right side.
anonymous
  • anonymous
I have 2 different answers bcoz I can't remember if it's correct to cross multiply it!
anonymous
  • anonymous
\[\frac{4}{3}\times\frac{3x}{4} ≥-6\times \frac{4}{3}\]\[\frac{4\times3x}{3\times 4} ≥\frac{-6\times 4}{3}\]
anonymous
  • anonymous
If you don't understand / can't handle this, just use the first method I told you: 1. Multiply both sides by 4 2. Divide both sides by 3
anonymous
  • anonymous
I've got x≥-8 is my answer correct?
HELP!!!!
  • HELP!!!!
-1
anonymous
  • anonymous
-8 is right...
anonymous
  • anonymous
I mean x≥-8
anonymous
  • anonymous
|dw:1355237549488:dw|
anonymous
  • anonymous
that's my answer ?right? yes I got it!
anonymous
  • anonymous
That's your answer :)
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
|dw:1355237691283:dw|
anonymous
  • anonymous
Welcome :)
anonymous
  • anonymous
|dw:1355237876145:dw||dw:1355237936952:dw|

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