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\[sin(x+iy)=sin(x)cos(iy)+sin(iy)cos(x)=sin(x)cosh(y)+isinh(y)cos(x)\]
\[sin(x+iy)^2=?\]
\[sin(x+iy)=\sqrt{sin^2xcosh^2y+sinh^2ycos^2x}\]
\[sin(x+iy)^2=sin^2xcosh^2y+sinh^2ycos^2x\]
 one year ago
 one year ago
\[sin(x+iy)=sin(x)cos(iy)+sin(iy)cos(x)=sin(x)cosh(y)+isinh(y)cos(x)\] \[sin(x+iy)^2=?\] \[sin(x+iy)=\sqrt{sin^2xcosh^2y+sinh^2ycos^2x}\] \[sin(x+iy)^2=sin^2xcosh^2y+sinh^2ycos^2x\]
 one year ago
 one year ago

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henpenBest ResponseYou've already chosen the best response.0
How to get this to equal \[sin^2x+sinh^2y\]?
 one year ago

henpenBest ResponseYou've already chosen the best response.0
\[\sin^2x(1\cosh^2y)=\sinh^2y(\cos^2x1)\]
 one year ago

henpenBest ResponseYou've already chosen the best response.0
\[\cos^2x1=\sin^2x\] \[1\cosh^2y=\sinh^2y\] Yay!
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
haha...u got it almost the same moment i got it..
 one year ago
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