Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing
henpen
Group Title
\[sin(x+iy)=sin(x)cos(iy)+sin(iy)cos(x)=sin(x)cosh(y)+isinh(y)cos(x)\]
\[sin(x+iy)^2=?\]
\[sin(x+iy)=\sqrt{sin^2xcosh^2y+sinh^2ycos^2x}\]
\[sin(x+iy)^2=sin^2xcosh^2y+sinh^2ycos^2x\]
 2 years ago
 2 years ago
henpen Group Title
\[sin(x+iy)=sin(x)cos(iy)+sin(iy)cos(x)=sin(x)cosh(y)+isinh(y)cos(x)\] \[sin(x+iy)^2=?\] \[sin(x+iy)=\sqrt{sin^2xcosh^2y+sinh^2ycos^2x}\] \[sin(x+iy)^2=sin^2xcosh^2y+sinh^2ycos^2x\]
 2 years ago
 2 years ago

This Question is Closed

henpen Group TitleBest ResponseYou've already chosen the best response.0
How to get this to equal \[sin^2x+sinh^2y\]?
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[\sin^2x(1\cosh^2y)=\sinh^2y(\cos^2x1)\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[\cos^2x1=\sin^2x\] \[1\cosh^2y=\sinh^2y\] Yay!
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
haha...u got it almost the same moment i got it..
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.