A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1I got \[y=0, x=2\pi n\]Correct?

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1But are these the only solutions?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1they are already infinite....and u know y must be 0 cos sin of imaginary number can't be real

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sin(x+iy)=\sin x \cosh y+i \cos x \sinh y\]

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1Cosine can cosh is a real function. It's imaginary for reals, however

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1cosine can never be imaginary hyperbolic cos can be...i think this is your point...

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1Yes. Thanks, I've got it now.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.