anonymous
  • anonymous
Solve \[\sin(x+iy)=0\]
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
I got \[y=0, x=2\pi n\]Correct?
hartnn
  • hartnn
seems correct.
anonymous
  • anonymous
But are these the only solutions?

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hartnn
  • hartnn
they are already infinite....and u know y must be 0 cos sin of imaginary number can't be real
anonymous
  • anonymous
\[\sin(x+iy)=\sin x \cosh y+i \cos x \sinh y\]
hartnn
  • hartnn
*because sin of...
anonymous
  • anonymous
Cosine can- cosh is a real function. It's imaginary for reals, however
hartnn
  • hartnn
cosine can never be imaginary hyperbolic cos can be...i think this is your point...
anonymous
  • anonymous
Yes. Thanks, I've got it now.

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