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spndshBest ResponseYou've already chosen the best response.0
do i distribute the 1/2 or the (a+b)?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
if i remember properly, cX(a.b) is the scalar triple product or box product denoted by [a b c] ans a. [a b c] = b. [a b c] = c. [a b c] = 0 so if u distribute (a+b), you'll get final answer as 0
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
also [na mb pc] = mnp [a b c ]
 one year ago

spndshBest ResponseYou've already chosen the best response.0
so i wouldn't simplify the inside of the brackets?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
i think i misinterpreted the question....
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
=0 + 1/2 [a c b]+ 1/2 b . 2c X a + 1/2 b . c X b =0 + 1/2 [a c b]+1/2 [b c a]+ 1/2[b c b] =0 1/2 [a b c] +1/2 [a b c] + 0 =0+0+0=0 now this seems right.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
if you could understand.... ask if there is any doubt in any step.
 one year ago

spndshBest ResponseYou've already chosen the best response.0
just one question whats the operation inside the bracket i.e [b c a]?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
cyclic change doesn't change sign [a b c] = [b c a] = [c a b] else, sign changes [a b c] = [a c b ] = [b a c]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
if any 2 or more vectors are same, then box product =0 [a a b] = [b b a] = ... = 0
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
or u meant to ask [a b c] = a.bXc ?
 one year ago
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