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spndsh
 2 years ago
Best ResponseYou've already chosen the best response.0do i distribute the 1/2 or the (a+b)?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1if i remember properly, cX(a.b) is the scalar triple product or box product denoted by [a b c] ans a. [a b c] = b. [a b c] = c. [a b c] = 0 so if u distribute (a+b), you'll get final answer as 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1also [na mb pc] = mnp [a b c ]

spndsh
 2 years ago
Best ResponseYou've already chosen the best response.0so i wouldn't simplify the inside of the brackets?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1i think i misinterpreted the question....

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1=0 + 1/2 [a c b]+ 1/2 b . 2c X a + 1/2 b . c X b =0 + 1/2 [a c b]+1/2 [b c a]+ 1/2[b c b] =0 1/2 [a b c] +1/2 [a b c] + 0 =0+0+0=0 now this seems right.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1if you could understand.... ask if there is any doubt in any step.

spndsh
 2 years ago
Best ResponseYou've already chosen the best response.0just one question whats the operation inside the bracket i.e [b c a]?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1cyclic change doesn't change sign [a b c] = [b c a] = [c a b] else, sign changes [a b c] = [a c b ] = [b a c]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1if any 2 or more vectors are same, then box product =0 [a a b] = [b b a] = ... = 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1or u meant to ask [a b c] = a.bXc ?
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