Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Solve the equation by finding square roots 32x^2=50

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

start by diving each side by 32
I have and got 2 now i have no idea what to do. The answers are -4/5,4/5 -25/16, 25/16 -16/25, 16/25 -5/4, 5/4
Try to write everything down step by step. Begin with surdawi's idea:\[32x^2=50 \rightarrow x^2=\frac{ 32 }{ 50 }\]You could now go on and take the root straightwawy, but it is much better to simplify the fraction first!\[x^2=\frac{ 32 }{ 50 }=\frac{ 16 }{ 25 }=\frac{ 4^2 }{ 5^2 }\]Now I think you can see the two numbers that satisfy the equation!

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Sorry, typo! I did it upside down :( It is of course:\[x^2=\frac{ 50 }{ 32 }=\frac{ 25 }{ 16 }=\frac{ 5^2 }{ 4^2 }\]
so it is -5/4, 5/4 ?
It is!!
would you mind helping me with another one?
No problem!

Not the answer you are looking for?

Search for more explanations.

Ask your own question