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joshi Group Title

If you throw a ball upwards from a building at x velocity, when it's coming back down and is at a point that it has the same height as it did initially; is the v the same? I don't know i'm having conceptual problems; here's a question i had a problem with: Ball A is thrown vertically upward with a speed of 19.6 m/s from the top edge of a high building. As it passes the edge on the way down, a second ball, B, is thrown downward at 19.6 m/s. Which of the following is correct? Ball A hits the ground before B. The two balls hit the ground at the same time. Ball B hits the ground before A.

  • one year ago
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  1. cherio12 Group Title
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    When you through a ball up it follows a parabolic curve. So for the first one the magnitude of v will be the same as when you first threw it. The only difference is that the velocity is now negative. The balls will hit at the same time

    • one year ago
  2. cherio12 Group Title
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    does that make sense?

    • one year ago
  3. humaira Group Title
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    3rd option is correct,beacause ball A should have to cover two paths, one is upward and the second is downward so A ball reaches next to ball B

    • one year ago
  4. cherio12 Group Title
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    |dw:1355325334184:dw|

    • one year ago
  5. cherio12 Group Title
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    The first ball follows the parabolic looking thing. When it comes back down to the same height that it was thrown at its velocity will be -19.6m/s which is the same speed the second ball is being thrown at. So they will hit at the same time

    • one year ago
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