anonymous
  • anonymous
If you throw a ball upwards from a building at x velocity, when it's coming back down and is at a point that it has the same height as it did initially; is the v the same? I don't know i'm having conceptual problems; here's a question i had a problem with: Ball A is thrown vertically upward with a speed of 19.6 m/s from the top edge of a high building. As it passes the edge on the way down, a second ball, B, is thrown downward at 19.6 m/s. Which of the following is correct? Ball A hits the ground before B. The two balls hit the ground at the same time. Ball B hits the ground before A.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
When you through a ball up it follows a parabolic curve. So for the first one the magnitude of v will be the same as when you first threw it. The only difference is that the velocity is now negative. The balls will hit at the same time
anonymous
  • anonymous
does that make sense?
anonymous
  • anonymous
3rd option is correct,beacause ball A should have to cover two paths, one is upward and the second is downward so A ball reaches next to ball B

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1355325334184:dw|
anonymous
  • anonymous
The first ball follows the parabolic looking thing. When it comes back down to the same height that it was thrown at its velocity will be -19.6m/s which is the same speed the second ball is being thrown at. So they will hit at the same time

Looking for something else?

Not the answer you are looking for? Search for more explanations.