Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

TMA76

  • 3 years ago

A 1.00 m long pendulum in simple harmonic motion sits on the surface of Mars. It has a period of 3.26 s. What is the acceleration due to gravity on Mars?

  • This Question is Closed
  1. TMA76
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. TMA76
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how do I do the formula on a calculator?

  3. cherio12
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay so there is a formula for a simple harmonic pendulum\[\omega^2=g/L\]

  4. cherio12
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    omega (w) also is equal to 2pi/T

  5. cherio12
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you are looking for g

  6. cherio12
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    T is your time, L is the length

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy