Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

PresleyramBest ResponseYou've already chosen the best response.0
dw:1355298946753:dw
 one year ago

nubeerBest ResponseYou've already chosen the best response.0
u can start by squaring both sides.
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
Before running off it it smart to take a look at two things: 1. The number under the radical, 6x+2 2. The result of the square root, x1 If you think about it, both numbers must be >=0! 6x+2 >=0 because there is no (real) square root of a negative number. x+1 >=0 because it's a square root and that is >=0 by definition.
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
This means that you answers are restricted two ways: 1. 6x+2>=0, so 6x>=2, x>=2/6, x>=1/3 2. x1>=0, so x>=1 BOTH must hold, so we combine them: x>=1. Whatever "solutions" you may find, they MUST be >= 1. Now square everything in sight: (x1)² = 6x+2 Work out the brackets Everything to the left side of the =sign Factorize, or use abcformula Check the solutions! Only if they are >= 1 they are really solutions. Reason for this nitpicking: by squaring everything, you lose the information about the square root and you could get fake solutions...
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
Oops, typo: 6x>=2, so x>= 1/3 Makes no difference: x >=1 anyway.
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
@nubeer: I wouldn't *start* with squaring, see above reasoning...
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
yw! Have you got the answer?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.