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ze4life

  • 2 years ago

prove:if an isosceles triangle has an altitude from the vertex to the base,then the altitude bisects the vertex angles given:ABC is isosceles;CD is the altitude to base AB to prove:CD bisects <ACB plan:?

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  1. ze4life
    • 2 years ago
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    plz help people

  2. ze4life
    • 2 years ago
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    |dw:1355266119270:dw|

  3. ze4life
    • 2 years ago
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    can someone plz help

  4. Brittni0605
    • 2 years ago
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    Ohh, geometry..grr..not confident in helping with proofs. I'm sorry. Ask @jim_thompson5910

  5. ze4life
    • 2 years ago
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    its alright thnxs

  6. jim_thompson5910
    • 2 years ago
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    Hint: |dw:1355350311633:dw|

  7. jim_thompson5910
    • 2 years ago
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    |dw:1355350385782:dw|

  8. ze4life
    • 2 years ago
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    what do u mean? explain plz

  9. jim_thompson5910
    • 2 years ago
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    AC = BC because this is an isosceles triangle

  10. jim_thompson5910
    • 2 years ago
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    CD = CD (reflexive property)

  11. jim_thompson5910
    • 2 years ago
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    and angle CDB is a right angle because CD is an altitude

  12. ze4life
    • 2 years ago
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    oh okay thnxs

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