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anonymous
 4 years ago
Solve x  8 > 2.
Answer
x > 10
x > 6
x > 10
x > 6
anonymous
 4 years ago
Solve x  8 > 2. Answer x > 10 x > 6 x > 10 x > 6

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you add 8 to both sides and then u get ur awnser

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Solve 4x > 12. Answer x > 3 x > 48 x < 3 x < 48

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0devide by 4 and u get c

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1x  8 > 2 x  8+8 > 2+8 x + 0 > 6 x > 6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the sign switched because u devide by a negative

Fools101
 4 years ago
Best ResponseYou've already chosen the best response.0is B. x>6 http://www.mathway.com/answer.aspx?p=calg?p=SMB15xSMB15SMB158SMB15SMB03SMB152?p=3?p=?p=?p=?p=?p=0?p=?p=0?p=?p=?p=SolveSMB15theSMB15Inequality ~Jess~

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1355276218950:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How about the 2nd one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1355276332574:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The symbol gets flipped around when dividing by negative number.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Solve the inequality, 3x  2 < 5. Answer x < 7/3 x > 7/3 x < 1 x > 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1355276463784:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Which of the following is a solution of the compound inequality 1 < 2n + 1 < 5? Answer 1 < n < 5 n > 2 or n < 1 1 < n < 2 n < 2 or n > 4

Fools101
 4 years ago
Best ResponseYou've already chosen the best response.0is C... I think http://www.mathway.com/answer.aspx?p=calg?p=1SMB15SMB02SMB152nSMB15+SMB151SMB15SMB02SMB155?p=5?p=?p=?p=?p=?p=0?p=?p=0?p=?p=?p=SolveSMB15theSMB15IntervalSMB15Inequality ~Jess~
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