A community for students.
Here's the question you clicked on:
 0 viewing
SamuelAlden917
 2 years ago
What is the range of y = 5x 2 if the domain is {3, 1, 0, 1, 3}?
Answer
{13, 3, 2, 3, 13}
{12, 3, 0, 3, 13}
{17, 7, 2, 3, 13}
SamuelAlden917
 2 years ago
What is the range of y = 5x 2 if the domain is {3, 1, 0, 1, 3}? Answer {13, 3, 2, 3, 13} {12, 3, 0, 3, 13} {17, 7, 2, 3, 13}

This Question is Closed

knick032
 2 years ago
Best ResponseYou've already chosen the best response.1Plug all the values of the domain in for x. The answers you get will be the range.

SamuelAlden917
 2 years ago
Best ResponseYou've already chosen the best response.0Im sorry. What is the answer?

knick032
 2 years ago
Best ResponseYou've already chosen the best response.1I explicitly told you how to find the answer. It doesn't get any easier than that.

knick032
 2 years ago
Best ResponseYou've already chosen the best response.1When you plug 3 into the equation for x, what number do you get for y?

knick032
 2 years ago
Best ResponseYou've already chosen the best response.1Incorrect. Let's just do 5 times 3. One of your hands has 5 fingers, right? How many fingers would you have if you had 3 hands?

knick032
 2 years ago
Best ResponseYou've already chosen the best response.1Yes. But since we're multiplying 5 times negative 3, we put a negative sign in front of the answer. So 5 times 3 = 15. In the original equation, it says y = 5x  2. So now you need to solve: 15 minus 2.

knick032
 2 years ago
Best ResponseYou've already chosen the best response.1Actually, since we're subtracting from a negative number, the answer will be "more negative." Another way to think of it is (15+2). So you would solve for 15+2, and then put a negative sign in front of it. What do you get?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.