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butterflyprincess

  • 3 years ago

H E L P : Cos (13pi/12 ) Use Half Angle ID to simplify ~

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  1. butterflyprincess
    • 3 years ago
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    I got : -root 3 - root 6 / 4 Is that what you got..?

  2. Venomblast
    • 3 years ago
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    radian or degree?

  3. butterflyprincess
    • 3 years ago
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    What do you mean? You just use that ID to simplify?

  4. Venomblast
    • 3 years ago
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    but i dont what ID.

  5. jim_thompson5910
    • 3 years ago
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    \[\Large \cos\left(\frac{13\pi}{12}\right) = \cos\left(\frac{1}{2}\cdot\frac{13\pi}{6}\right)\] \[\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{1+\cos\left(\cdot\frac{13\pi}{6}\right)}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{1}{2}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{2}{4}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = -\sqrt{\frac{2+\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = -\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = -\frac{\sqrt{2+\sqrt{3}}}{2}\]

  6. butterflyprincess
    • 3 years ago
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    cool thnx! (:

  7. jim_thompson5910
    • 3 years ago
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    yw

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