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butterflyprincess
Group Title
H E L P :
Cos (13pi/12 ) Use Half Angle ID to simplify ~
 one year ago
 one year ago
butterflyprincess Group Title
H E L P : Cos (13pi/12 ) Use Half Angle ID to simplify ~
 one year ago
 one year ago

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butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
I got : root 3  root 6 / 4 Is that what you got..?
 one year ago

Venomblast Group TitleBest ResponseYou've already chosen the best response.0
radian or degree?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
What do you mean? You just use that ID to simplify?
 one year ago

Venomblast Group TitleBest ResponseYou've already chosen the best response.0
but i dont what ID.
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
\[\Large \cos\left(\frac{13\pi}{12}\right) = \cos\left(\frac{1}{2}\cdot\frac{13\pi}{6}\right)\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1+\cos\left(\cdot\frac{13\pi}{6}\right)}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1}{2}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{2}{4}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{2+\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \frac{\sqrt{2+\sqrt{3}}}{2}\]
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
cool thnx! (:
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
yw
 one year ago
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