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butterflyprincess
 2 years ago
Best ResponseYou've already chosen the best response.0I got : root 3  root 6 / 4 Is that what you got..?

butterflyprincess
 2 years ago
Best ResponseYou've already chosen the best response.0What do you mean? You just use that ID to simplify?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1\[\Large \cos\left(\frac{13\pi}{12}\right) = \cos\left(\frac{1}{2}\cdot\frac{13\pi}{6}\right)\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1+\cos\left(\cdot\frac{13\pi}{6}\right)}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1}{2}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{2}{4}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{2+\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \frac{\sqrt{2+\sqrt{3}}}{2}\]

butterflyprincess
 2 years ago
Best ResponseYou've already chosen the best response.0cool thnx! (:
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