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H E L P :
Cos (13pi/12 ) Use Half Angle ID to simplify ~
 one year ago
 one year ago
H E L P : Cos (13pi/12 ) Use Half Angle ID to simplify ~
 one year ago
 one year ago

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butterflyprincessBest ResponseYou've already chosen the best response.0
I got : root 3  root 6 / 4 Is that what you got..?
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
What do you mean? You just use that ID to simplify?
 one year ago

VenomblastBest ResponseYou've already chosen the best response.0
but i dont what ID.
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
\[\Large \cos\left(\frac{13\pi}{12}\right) = \cos\left(\frac{1}{2}\cdot\frac{13\pi}{6}\right)\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1+\cos\left(\cdot\frac{13\pi}{6}\right)}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{1}{2}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{2}{4}+\frac{\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \sqrt{\frac{2+\sqrt{3}}{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}\] \[\Large \cos\left(\frac{13\pi}{12}\right) = \frac{\sqrt{2+\sqrt{3}}}{2}\]
 one year ago

butterflyprincessBest ResponseYou've already chosen the best response.0
cool thnx! (:
 one year ago
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