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pmonrreal

  • 3 years ago

A crane lifts a 425 kg steel beam vertically a distance of 66 m. How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces

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  1. Hunus
    • 3 years ago
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    \[W=F*d\] \[F=ma\] \[W=(ma)*d\] \[W=((425 kg)(\frac{1.8 m}{s^2}))*66m\]

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