## mollyann help one year ago one year ago

1. mollyann

2. Nurali

i think A.

3. jim_thompson5910

$\Large \frac{\frac{x^2+2x+1}{x-2}}{\frac{x^2-1}{x^2-4}}$ is the same as $\Large \frac{x^2+2x+1}{x-2} \times \frac{x^2-4}{x^2-1}$

4. jim_thompson5910

and you can combine the fractions to get $\Large \frac{(x^2+2x+1)(x^2-4)}{(x-2)(x^2-1)}$

5. jim_thompson5910

then factor everything to get $\Large \frac{(x+1)(x+1)(x-2)(x+2)}{(x-2)(x-1)(x+1)}$

6. mollyann

so what would the answer be ?

7. Nurali

A is correct lol.

8. jim_thompson5910

yes, cancelling the common factors leads to $\Large \frac{(x+1)(x+2)}{x-1}$ which is A