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jim_thompson5910Best ResponseYou've already chosen the best response.0
\[\Large \frac{\frac{x^2+2x+1}{x2}}{\frac{x^21}{x^24}}\] is the same as \[\Large \frac{x^2+2x+1}{x2} \times \frac{x^24}{x^21}\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
and you can combine the fractions to get \[\Large \frac{(x^2+2x+1)(x^24)}{(x2)(x^21)}\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
then factor everything to get \[\Large \frac{(x+1)(x+1)(x2)(x+2)}{(x2)(x1)(x+1)}\]
 one year ago

mollyannBest ResponseYou've already chosen the best response.0
so what would the answer be ?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
yes, cancelling the common factors leads to \[\Large \frac{(x+1)(x+2)}{x1}\] which is A
 one year ago
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