anonymous
  • anonymous
Find dy/dx. y=5^(ln(x^2)+3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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abb0t
  • abb0t
\[a^x \ln(a)\]
anonymous
  • anonymous
thank you!:)
abb0t
  • abb0t
fa sho! GL!

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More answers

RadEn
  • RadEn
lol, the clue incomplete... use chain rule : y=x^2 ---> y'=2x v=ln(u) ---> v'=1/u w=5^v ---> w'=5^v * ln(5)
anonymous
  • anonymous
ok, i got this.. y'= 5^(ln((x^2)+3)) *ln 5*((2x)/((x^2)+3)) ..is it right?
RadEn
  • RadEn
for the power of 5, is {ln(x^2) + 3} or ln(x^2+3)
anonymous
  • anonymous
i did include that, im just not sure if i did it right?, do i have to put (1/5) for ln5?
RadEn
  • RadEn
before verify, i want to asking u is ur question |dw:1355302758870:dw|
RadEn
  • RadEn
which one, the 1st or the 2nd ?
anonymous
  • anonymous
the 2nd one
RadEn
  • RadEn
hohohoo... ok,, u have typo above, right ?
anonymous
  • anonymous
i think so,..
anonymous
  • anonymous
but yea, my question is to derive the 2nd one
RadEn
  • RadEn
if u have typed ur question like the original above, the result will be difference :) OK,,,, now U RE RIGHT :*
anonymous
  • anonymous
so im right?
RadEn
  • RadEn
sure... nice answer.
RadEn
  • RadEn
but if ur question y=5^(ln(x^2)+3), so the answer will be y' = (2/x) * 5^(ln(x^2)+3) * ln(5)
anonymous
  • anonymous
ok then, well its like the second one
RadEn
  • RadEn
yea... be careful in type the equation ^^
anonymous
  • anonymous
ok thanks!:)
RadEn
  • RadEn
very welcome

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