A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0lol, the clue incomplete... use chain rule : y=x^2 > y'=2x v=ln(u) > v'=1/u w=5^v > w'=5^v * ln(5)

jcamargo93
 2 years ago
Best ResponseYou've already chosen the best response.0ok, i got this.. y'= 5^(ln((x^2)+3)) *ln 5*((2x)/((x^2)+3)) ..is it right?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0for the power of 5, is {ln(x^2) + 3} or ln(x^2+3)

jcamargo93
 2 years ago
Best ResponseYou've already chosen the best response.0i did include that, im just not sure if i did it right?, do i have to put (1/5) for ln5?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0before verify, i want to asking u is ur question dw:1355302758870:dw

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0which one, the 1st or the 2nd ?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0hohohoo... ok,, u have typo above, right ?

jcamargo93
 2 years ago
Best ResponseYou've already chosen the best response.0but yea, my question is to derive the 2nd one

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0if u have typed ur question like the original above, the result will be difference :) OK,,,, now U RE RIGHT :*

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0but if ur question y=5^(ln(x^2)+3), so the answer will be y' = (2/x) * 5^(ln(x^2)+3) * ln(5)

jcamargo93
 2 years ago
Best ResponseYou've already chosen the best response.0ok then, well its like the second one

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0yea... be careful in type the equation ^^
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.