## jcamargo93 2 years ago Find dy/dx. y=5^(ln(x^2)+3)

1. abb0t

$a^x \ln(a)$

2. jcamargo93

thank you!:)

3. abb0t

fa sho! GL!

lol, the clue incomplete... use chain rule : y=x^2 ---> y'=2x v=ln(u) ---> v'=1/u w=5^v ---> w'=5^v * ln(5)

5. jcamargo93

ok, i got this.. y'= 5^(ln((x^2)+3)) *ln 5*((2x)/((x^2)+3)) ..is it right?

for the power of 5, is {ln(x^2) + 3} or ln(x^2+3)

7. jcamargo93

i did include that, im just not sure if i did it right?, do i have to put (1/5) for ln5?

before verify, i want to asking u is ur question |dw:1355302758870:dw|

which one, the 1st or the 2nd ?

10. jcamargo93

the 2nd one

hohohoo... ok,, u have typo above, right ?

12. jcamargo93

i think so,..

13. jcamargo93

but yea, my question is to derive the 2nd one

if u have typed ur question like the original above, the result will be difference :) OK,,,, now U RE RIGHT :*

15. jcamargo93

so im right?

but if ur question y=5^(ln(x^2)+3), so the answer will be y' = (2/x) * 5^(ln(x^2)+3) * ln(5)

18. jcamargo93

ok then, well its like the second one

yea... be careful in type the equation ^^

20. jcamargo93

ok thanks!:)