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anonymous
 3 years ago
Find dy/dx. y=5^(ln(x^2)+3)
anonymous
 3 years ago
Find dy/dx. y=5^(ln(x^2)+3)

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RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0lol, the clue incomplete... use chain rule : y=x^2 > y'=2x v=ln(u) > v'=1/u w=5^v > w'=5^v * ln(5)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, i got this.. y'= 5^(ln((x^2)+3)) *ln 5*((2x)/((x^2)+3)) ..is it right?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0for the power of 5, is {ln(x^2) + 3} or ln(x^2+3)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i did include that, im just not sure if i did it right?, do i have to put (1/5) for ln5?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0before verify, i want to asking u is ur question dw:1355302758870:dw

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0which one, the 1st or the 2nd ?

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0hohohoo... ok,, u have typo above, right ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but yea, my question is to derive the 2nd one

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0if u have typed ur question like the original above, the result will be difference :) OK,,,, now U RE RIGHT :*

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0but if ur question y=5^(ln(x^2)+3), so the answer will be y' = (2/x) * 5^(ln(x^2)+3) * ln(5)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok then, well its like the second one

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0yea... be careful in type the equation ^^
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