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mike12

  • 2 years ago

6(x^3-64)

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  1. eyust707
    • 2 years ago
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    simplify?

  2. mike12
    • 2 years ago
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    how

  3. Callisto
    • 2 years ago
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    Do you need to factorize it or expand it?

  4. mike12
    • 2 years ago
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    factorize

  5. Callisto
    • 2 years ago
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    Use \(a^3 - b^3 = (a-b)(a^2+ab+b^2)\)

  6. Callisto
    • 2 years ago
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    FYI, 64=4^3

  7. abb0t
    • 2 years ago
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    I believe the answer is: \[6x^3+384\]

  8. mike12
    • 2 years ago
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    i started off with 6x^3 +384

  9. joyap03
    • 2 years ago
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    distribution :) sir abbot is right

  10. Callisto
    • 2 years ago
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    Factorize.. not expand..

  11. Callisto
    • 2 years ago
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    And if you started from 6x^3 +384, you shouldn't get 6(x^3-64)...

  12. mike12
    • 2 years ago
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    i got 6(x^3-64)

  13. Callisto
    • 2 years ago
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    What is the original question?

  14. mike12
    • 2 years ago
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    factor 6x^3-384

  15. Silenthill
    • 2 years ago
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    = 6x^3-384 or 6(x-4)(x^2+4x+16)

  16. Callisto
    • 2 years ago
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    @mike12 Then you did right. 6x^3-384 = 6(x^3 - 64) Note that 64 can be written as 4^3, so you get = 6(x^3 - 4^3) Next apply the identity \(a^3-b^3 = (a-b)(a^2+ab+b^2)\) to factorize x^3 - 4^3. Can you do it?

  17. mike12
    • 2 years ago
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    ill try

  18. mike12
    • 2 years ago
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    give me a second

  19. Callisto
    • 2 years ago
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    Take your time :)

  20. mike12
    • 2 years ago
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    lol yeah im pretty lost

  21. Callisto
    • 2 years ago
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    Where?

  22. mike12
    • 2 years ago
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    applying the identity

  23. Callisto
    • 2 years ago
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    Have you learnt that identity yet?

  24. mike12
    • 2 years ago
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    yeah but actually trying to sub it in...having troubles

  25. Callisto
    • 2 years ago
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    What troubles? Can you show your work?

  26. mike12
    • 2 years ago
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    honestly just plugging in the equation... i dont know what to plug in or where

  27. Callisto
    • 2 years ago
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    Compare \(x^3 - 4^3 \) and \(a^3-b^3\) Can you identify what is a and b?

  28. mike12
    • 2 years ago
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    yeah

  29. Callisto
    • 2 years ago
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    What are they then?

  30. Callisto
    • 2 years ago
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    @mike12 What are a and b...???

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