anonymous
  • anonymous
6(x^3-64)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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eyust707
  • eyust707
simplify?
anonymous
  • anonymous
how
Callisto
  • Callisto
Do you need to factorize it or expand it?

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More answers

anonymous
  • anonymous
factorize
Callisto
  • Callisto
Use \(a^3 - b^3 = (a-b)(a^2+ab+b^2)\)
Callisto
  • Callisto
FYI, 64=4^3
abb0t
  • abb0t
I believe the answer is: \[6x^3+384\]
anonymous
  • anonymous
i started off with 6x^3 +384
anonymous
  • anonymous
distribution :) sir abbot is right
Callisto
  • Callisto
Factorize.. not expand..
Callisto
  • Callisto
And if you started from 6x^3 +384, you shouldn't get 6(x^3-64)...
anonymous
  • anonymous
i got 6(x^3-64)
Callisto
  • Callisto
What is the original question?
anonymous
  • anonymous
factor 6x^3-384
anonymous
  • anonymous
= 6x^3-384 or 6(x-4)(x^2+4x+16)
Callisto
  • Callisto
@mike12 Then you did right. 6x^3-384 = 6(x^3 - 64) Note that 64 can be written as 4^3, so you get = 6(x^3 - 4^3) Next apply the identity \(a^3-b^3 = (a-b)(a^2+ab+b^2)\) to factorize x^3 - 4^3. Can you do it?
anonymous
  • anonymous
ill try
anonymous
  • anonymous
give me a second
Callisto
  • Callisto
Take your time :)
anonymous
  • anonymous
lol yeah im pretty lost
Callisto
  • Callisto
Where?
anonymous
  • anonymous
applying the identity
Callisto
  • Callisto
Have you learnt that identity yet?
anonymous
  • anonymous
yeah but actually trying to sub it in...having troubles
Callisto
  • Callisto
What troubles? Can you show your work?
anonymous
  • anonymous
honestly just plugging in the equation... i dont know what to plug in or where
Callisto
  • Callisto
Compare \(x^3 - 4^3 \) and \(a^3-b^3\) Can you identify what is a and b?
anonymous
  • anonymous
yeah
Callisto
  • Callisto
What are they then?
Callisto
  • Callisto
@mike12 What are a and b...???

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