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Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Do you need to factorize it or expand it?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Use \(a^3  b^3 = (ab)(a^2+ab+b^2)\)

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.0I believe the answer is: \[6x^3+384\]

mike12
 2 years ago
Best ResponseYou've already chosen the best response.1i started off with 6x^3 +384

joyap03
 2 years ago
Best ResponseYou've already chosen the best response.0distribution :) sir abbot is right

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Factorize.. not expand..

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0And if you started from 6x^3 +384, you shouldn't get 6(x^364)...

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0What is the original question?

Silenthill
 2 years ago
Best ResponseYou've already chosen the best response.0= 6x^3384 or 6(x4)(x^2+4x+16)

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0@mike12 Then you did right. 6x^3384 = 6(x^3  64) Note that 64 can be written as 4^3, so you get = 6(x^3  4^3) Next apply the identity \(a^3b^3 = (ab)(a^2+ab+b^2)\) to factorize x^3  4^3. Can you do it?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Have you learnt that identity yet?

mike12
 2 years ago
Best ResponseYou've already chosen the best response.1yeah but actually trying to sub it in...having troubles

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0What troubles? Can you show your work?

mike12
 2 years ago
Best ResponseYou've already chosen the best response.1honestly just plugging in the equation... i dont know what to plug in or where

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Compare \(x^3  4^3 \) and \(a^3b^3\) Can you identify what is a and b?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0@mike12 What are a and b...???
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