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which equation ?

can u be more specific ?

x^2-64=0
i have to find out another way to make it true

whats the first way ?

x= -b(-+)(square route)b (squared )- 4 ac (divided by a)

8^2-64=0

x^2-64 =0
you can take 64 to other side
x^2 =64
then take square root on both side, what u get ?

I dont understand..

\[x = -b \pm \sqrt{?} ^{b}-4ac \ \div 2a\]

thats the quodratic equation